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我正在创建一个允许用户输入问题的搜索功能,然后我的代码将与我的 MySQL 数据库中已有的问题匹配尽可能多的单词,并根据匹配的单词数量显示前 5 个结果这个问题。

我使用count() 函数来计算匹配单词的数量,但是目前显示的结果显示为数据库中具有 50% 或更多单词匹配的前 5 个结果。我希望结果首先显示为最高匹配,然后对数据库中的每个结果进行向下处理,但只显示前 5 个。这是我的代码

<?php
    include("config.php");
    $search_term = filter_var($_GET["s"], FILTER_SANITIZE_STRING); //User enetered data
    $search_term = str_replace ("?", "", $search_term); //remove any question marks from string
    $search_count = str_word_count($search_term);  //count words of string entered by user
    $array = explode(" ", $search_term); //Seperate user enterd data

    foreach ($array as $key=>$word) {
        $array[$key] = " title LIKE '%".$word."%' "; //creates condition for MySQL query
    }

    $q = "SELECT * FROM posts WHERE  " . implode(' OR ', $array); //Query to select data with word matches
    $r = mysql_query($q);
    $count = 0; //counter to limit results shown
    while($row = mysql_fetch_assoc($r)){
        $thetitle = $row['title']; //result from query
        $thetitle = str_replace ("?", "", $thetitle);  //remove any question marks from string
        $title_array[] = $thetitle;  //creating array for query results
        $newarray = explode(" ", $search_term); //Seperate user enterd data again
        foreach($title_array as $key => $value) {
            $thenewarray = explode(" ", $value); //Seperate each result from query
            $wordmatch = array_diff_key($thenewarray, array_flip($newarray));
            $result = array_intersect($newarray, $wordmatch);
            $matchingwords = count($result); //Count the number of matching words from
            //user entered data and the database query
        }

        if(mysql_num_rows($r)==0)//no result found
        {
            echo "<div id='search-status'>No result found!</div>";
        }
        else //result found
        {
            echo "<ul>";
            $title = $row['title'];
            $percentage = '.5'; //percentage to take of search word count
            $percent = $search_count - ($search_count * $percentage); //take percentage off word count
            if ($matchingwords >= $percent){

                ?>
            <li><a href='<?php echo $row['url']; ?>'><?php echo $title ?><i> &nbsp; No. matching words: <?php echo $matchingwords; ?></i></a></li>
            <?php

                $count++;
                if ($count == 5) {break;
                }
            }else{
            }
        }
        echo "</ul>";
    }
?>

下图显示了当我在搜索栏中搜索“如何制作自己的网站”时发生的情况。我已经在数据库中有几个问题要测试,它们都是相似的问题,最后一个条目与我提出的问题完全匹配,但由于它目前将它们显示为前 5 个数学结果,它忽略了完全匹配。这是该搜索的结果。 在此处输入图像描述

我添加了一些代码,显示每个问题中有多少单词匹配,以便您可以看到它工作得更好。巧合的是,它按升序显示数据库中的前 5 个匹配结果。

我需要添加什么代码来安排它,以便它首先显示整个数据库中最接近的匹配,然后是第二个最佳匹配,第三个等等......?

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1 回答 1

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您可以使用嵌套 SQL 查询,您可以在其中按计数排序,或者先将值加载到数组 php 数组,然后对数组进行排序。使用 SQL 非常高效 && 更快。

多维数组排序

select column1, column2,..., LENGTH(titlecolumn) - LENGTH(REPLACE(titlecolumn, '$search term', '')) AS nummatchwords from posts where " . implode(' OR ', $array) order by nummatchwords;
于 2012-08-04T13:57:06.987 回答