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我在我的程序中使用 AsyncTask 进行多线程处理，方法是在 10 秒后调用一个方法，但有这个异常：

08-04 11:49:29.565: E/log_tag(885): Error converting result java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()

请帮帮我！！

编辑：这是 AsyncTask 的代码：

  class Getphonenumber extends AsyncTask<String, Void, Void> {
         public Void doInBackground(String... p) {
          while (true) {
              getPhno();
           try {
            Thread.sleep(10000);
           } catch (InterruptedException ie) {
            ie.printStackTrace();
           }
          }
        }

        };

'getPhno()' 方法：

public void getPhno()
  {
      try{

            HttpClient httpclient = new DefaultHttpClient();
            HttpConnectionParams.setConnectionTimeout(httpclient.getParams(), 10000); //Timeout Limit
            List<NameValuePair> username = new ArrayList<NameValuePair>();
            username.add(new BasicNameValuePair("username", user));
            //Web Address
            HttpPost httppost = new HttpPost("http://www.starretailshop.com/Log/Retrieve.php");
            httppost.setEntity(new UrlEncodedFormEntity(username));
            HttpResponse response = httpclient.execute(httppost);
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            String responseBody = httpclient.execute(httppost,
                    responseHandler);

            Log.i("retrieve postData", response.getStatusLine().toString());
            InputStream content = response.getEntity().getContent();
            BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
            String s = "";
            while ((s = buffer.readLine()) != null) {

                sendMsg(s,msg);

            }

            }catch(Exception e){

                  Log.e("log_tag", "Error converting result "+e.toString());
            }
  }

'sendMsg' 方法：

private void sendMsg(String phoneNumber, String message)
    { 
       try{
            String phoneNumber1 = null;

           if(phoneNumber.startsWith("+"))
            {
                phoneNumber1 = phoneNumber.substring(3);

            }
            else if(phoneNumber.startsWith("0"))
            {
                phoneNumber1 = phoneNumber.substring(1);
            }
            else
            {
                phoneNumber1=phoneNumber;
            }
                PendingIntent pi = PendingIntent.getActivity(this, 0,
                    new Intent(), 0);                
                SmsManager sms = SmsManager.getDefault();
                sms.sendTextMessage(phoneNumber1, null, message, pi, null);
                Toast.makeText(this,"Msg sent to:" + phoneNumber1, Toast.LENGTH_LONG).show();
                phnoList.add(phoneNumber);
                phnoListd.add(phoneNumber1);
                //phnumber = phoneNumber;
                //================Update Database=====================

              try{
                  HttpClient httpclient = new DefaultHttpClient();
                  HttpConnectionParams.setConnectionTimeout(httpclient.getParams(), 10000); //Timeout Limit
                  List<NameValuePair> updatemsg = new ArrayList<NameValuePair>();
                  updatemsg.add(new BasicNameValuePair("outmsg1", message));
                  Calendar cal = Calendar.getInstance();
                  SimpleDateFormat sdf = new SimpleDateFormat("HH:m:ss dd-MM-yyyy");
                  String TimeStampDB = sdf.format(cal.getTime()); 
                  updatemsg.add(new BasicNameValuePair("currentdatetime1",TimeStampDB));
                  updatemsg.add(new BasicNameValuePair("mobileno",phoneNumber));

                    //Web Address
                    HttpPost httppost = new HttpPost("http://www.starretailshop.com/Log/Update1.php");
                    httppost.setEntity(new UrlEncodedFormEntity(updatemsg));
                    HttpResponse response = httpclient.execute(httppost);
                    ResponseHandler<String> responseHandler = new BasicResponseHandler();
                    String responseBody = httpclient.execute(httppost,
                            responseHandler);
                    Log.i("update1 postData", response.getStatusLine().toString());
                    }catch(Exception e){
                        Log.e("log_tag", "Error converting result "+e.toString());
                    }

                    //================================================
          }catch(Exception e)
          {
              e.printStackTrace();
              Toast.makeText(this,"Error occured", Toast.LENGTH_LONG).show();
          }


}

最后，我调用new Getphonenumber().execute();了一个按钮的 onClickListener。

4

3 回答 3

3

我认为问题在于，您正在尝试从后台线程更新 UI 组件。

例如，在你的 AsyncTask 中考虑这个方法，

protected Void doInBackground(String ... x) {
      while (true) {
       System.out.println(x[0]);
       try {
        Thread.sleep(1000);
       } catch (InterruptedException ie) {
        ie.printStackTrace();
       }
      }

这个方法就相当于一个后台线程。在 Andorid 中，您只能从主 UI 线程更新您的 UI，当您尝试从任何其他方法执行此操作时，您将收到此异常。

所以尽量避免这种情况。如果要更新 UI，请使用 AsyncTask 的 onPostExecute()。

编辑 1

这是你的问题。从 sendMsg 方法中删除吐司，它应该可以正常工作。

于 2012-08-04T06:41:25.403 回答
2

使用runOnUiThread从非 Ui Thread.like 更新 UI 作为您提供的代码。您正在显示来自后台线程的 Toast 消息，因此将 Toast 消息放入 runOnUiThread 中：

Current_Activity.this.runOnUiThread(new Runnable() {
  public void run() {

  Toast.makeText(this,"Msg sent to:" + phoneNumber1, Toast.LENGTH_LONG).show();
  }
});
于 2012-08-04T07:03:17.173 回答
1

不要在 doBackround 中创建睡眠线程，而是在 .execute() 之前执行它。我想这会有所帮助。

于 2012-08-04T06:50:36.220 回答