我刚刚写了一个小程序来测试一些东西,如下:
public class Main {
public static void main(String[] args){
ServerSocket serverSocket = null;
Socket clientSocket = null;
DataInputStream dataInputStream= null;
BufferedWriter bufferedWriter = null;
String line ;
try {
serverSocket = new ServerSocket(80);
clientSocket = serverSocket.accept();
dataInputStream = new DataInputStream(clientSocket.getInputStream());
while((line = dataInputStream.readLine()) != null){
System.out.println(line);
}
bufferedWriter = new BufferedWriter(new OutputStreamWriter(clientSocket.getOutputStream()));
bufferedWriter.write("HTTP/1.0 200 OK \n Date: Fri, 31 Dec 1999 23:59:59 GMT \n Content-Type: text/html \n Content-Length: 1354 \n <html>abcde<html/>");
bufferedWriter.flush();
} catch (IOException e) {
System.out.println("socket port cannot be opened.");
e.printStackTrace();
} finally{
try {
serverSocket.close();
bufferedWriter.close();
} catch (IOException e) {
System.out.println("socket port cannot be closed.");
e.printStackTrace();
}
}
}
}
我从网上找到了http响应格式,应该是正确的。问题是我的浏览器一直在等待响应数据(从旋转的标志确定),但数据没有返回成功。我犯了什么错误?
我通过在浏览器中键入“localhost”连接到 Java 程序,我可以在 Java 程序中打印出请求字符串,但只是无法发回响应。