5

以下查询旨在查找去医院的人数、去医院的总人数，然后将这两者相除以获得百分比。该表Claims有 200 万多行，并且确实具有正确的非聚集索引patientid, admissiondate, and dischargdate. 查询运行得足够快，但我对如何使它更有用很感兴趣。我希望能够在行中添加另一个代码，(hcpcs.hcpcs ='97001')并将更改percentRehabNotHomeHealth反映在另一列中。有没有可能不写一个大的、胖的连接语句来将两个查询的结果连接在一起？我知道通过添加额外的列，数学看起来不正确，但我现在并不担心。所需的示例输出：http: //imgur.com/BCLrd
数据库模式

在此处输入图像描述

select  h.hospitalname
    ,count(*) as visitCounts
    ,hospitalcounts
    ,round(count(*)/cast(hospitalcounts as float) *100,2) as percentRehabNotHomeHealth
    from Patient p
    inner join statecounties as sc on sc.countycode = p.countycode
    and sc.statecode = p.statecode
    inner join hospitals as h on h.npi=p.hospitalnpi
    inner join
    --this join adds the hospitalCounts column
    (
        select h.hospitalname, count(*) as hospitalCounts
            from hospitals as h
            inner join patient as p on p.hospitalnpi=h.npi
            where p.statecode='21' and h.statecode='21'
            group by h.hospitalname
    ) as t on t.hospitalname=h.hospitalname
    --this where exists clause gives the visitCounts column
    where h.stateCode='21' and p.statecode='21'
    and exists
    (
        select distinct p2.patientid
            from Patient as p2
            inner join Claims as c on c.patientid = p2.patientid
            and c.admissiondate = p2.admissiondate
            and c.dischargedate = p2.dischargedate
            inner join hcpcs on hcpcs.hcpcs=c.hcpcs
            inner join hospitals as h on h.npi=p2.hospitalnpi
            where (hcpcs.hcpcs ='97001' or hcpcs.hcpcs='9339' or hcpcs.hcpcs='97002')
            and p2.patientid=p.patientid 
    ) 
    and hospitalcounts > 10
    group by h.hospitalname, t.hospitalcounts
    having count(*)>10
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1 回答 1

4

您可能会查看 CTE（通用表表达式）来获得所需的内容。它将允许您获取汇总数据并将其加入到公共密钥的详细信息中。例如，我将您对子查询的联接修改为 CTE。

;with hospitalCounts as (
    select h.hospitalname, count(*) as hospitalCounts
    from hospitals as h
    inner join patient as p on p.hospitalnpi=h.npi
    where p.statecode='21' and h.statecode='21'
    group by h.hospitalname
)
select  h.hospitalname
    ,count(*) as visitCounts
    ,hospitalcounts
    ,round(count(*)/cast(hospitalcounts as float) *100,2) as percentRehabNotHomeHealth
from Patient p
inner join statecounties as sc on sc.countycode = p.countycode
and sc.statecode = p.statecode
inner join hospitals as h on h.npi=p.hospitalnpi
inner join hospitalCounts on t.hospitalname=h.hospitalname
--this where exists clause gives the visitCounts column
where h.stateCode='21' and p.statecode='21'
and exists
(
    select p2.patientid
        from Patient as p2
        inner join Claims as c on c.patientid = p2.patientid
        and c.admissiondate = p2.admissiondate
        and c.dischargedate = p2.dischargedate
        inner join hcpcs on hcpcs.hcpcs=c.hcpcs
        inner join hospitals as h on h.npi=p2.hospitalnpi
        where (hcpcs.hcpcs ='97001' or hcpcs.hcpcs='9339' or hcpcs.hcpcs='97002')
        and p2.patientid=p.patientid 
) 
and hospitalcounts > 10
group by h.hospitalname, t.hospitalcounts
having count(*)>10
于 2012-08-08T17:18:44.013 回答