php - 通过引用分配由 PHP 中的方法调用返回的数组？

Question

我需要循环每个$message收件人（收件人是一个array），如果出现问题，unset相应的收件人：

$recipients = &$message->getRecipients(); // array

// Do this now as arrays is going to be altered in the loop
$count = count($recipients);         

for($i = 0; $i <= $count; $i++):

    $response = $messageManager->send($recipients[$i], $content);

    // If not 200 OK remove the recipient from the message
    if($response->getStatusCode !== 200) unset($recipients[$i]); 

endfor;

但是 PHP 不会让我这样做，因为“只能通过引用分配变量”。除了重新分配数组之外，我还能做些什么：

$recipients = $message->getRecipients();

// Loop

$message->setRecipients($recipients);

编辑：不能使用 foreach 并通过引用传递当前元素：

$recipients = array('a', 'b', 'c');

foreach($recipients as &$recipient)
    unset($recipient);

echo count($recipients); // 3

Answer 1

你可以这样做：

$recipients = $message->getRecipients();      

foreach($recipients as $key => $recipient) :

    $response = $messageManager->send($recipient, $content);
    if($response->getStatusCode !== 200) unset($recipients[$key]); 

endforeach;

$message->setRecipients($recipients);