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我所拥有的是一长串代码，其中涉及读取不同的文件并最终将所有内容放入不同的 .csv

这是我所有的代码

import csv
import os.path
#open files + readlines
with open("C:/Users/Ivan Wong/Desktop/Placement/Lists of targets/Mouse/UCSC to Ensembl.csv", "r") as f:
    reader = csv.reader(f, delimiter = ',')
    #find files with the name in 1st row
    for row in reader:
        graph_filename = os.path.join("C:/Python27/Scripts/My scripts/Selenoprotein/NMD targets",row[0]+"_nt_counts.txt.png")
        if os.path.exists(graph_filename):
            y = row[0]+'_nt_counts.txt'  
            r = open('C:/Users/Ivan Wong/Desktop/Placement/fp_mesc_nochx/'+y, 'r')
            k = r.readlines()
            r.close
            del k[:1]
            k = map(lambda s: s.strip(), k)
            interger = map(int, k)   
            import itertools
            #adding the numbers for every 3 rows
            def grouper(n, iterable, fillvalue=None):
                "grouper(3, 'ABCDEFG', 'x') --> ABC DEF Gxx"
                args = [iter(iterable)] * n
                return itertools.izip_longest(*args, fillvalue=fillvalue)
            result = map(sum, grouper(3, interger, 0))       
            e = row[1]
            cDNA = open('C:/Users/Ivan Wong/Desktop/Placement/Downloaded seq/Mouse/cDNA.txt', 'r')
            seq = cDNA.readlines()
            # get all lines that have a gene name
            lineNum = 0;
            lineGenes = []
            for line in seq:
                lineNum = lineNum +1
                if '>' in line:
                    lineGenes.append(str(lineNum))
                if '>'+e in line:
                    lineBegin = lineNum

            cDNA.close

            # which gene is this
            index1 = lineGenes.index(str(lineBegin))
            lineEnd = lineGenes[index1+1]           
# linebegin and lineEnd now give you, where to look for your sequence, all that 
# you have to do is to read the lines between lineBegin and lineEnd in the file
# and make it into a single string.            
            lineEnd = lineGenes[index1+1]
            Lastline = int(lineEnd) -1

# in your code you have already made a list with all the lines (q), first delete
# \n and other symbols, then combine all lines into a big string of nucleotides (like this)     
            qq = seq[lineBegin:Lastline]
            qq = map(lambda s: s.strip(), qq)
            string  = ''
            for i in range(len(qq)):
                string = string + qq[i]
# now you want to get a list of triplets, again you can use the for loop:
# first get the length of the string
            lenString = len(string);
# this is your list codons
            listCodon = []
            for i in range(0,lenString/3): 
                listCodon.append(string[0+i*3:3+i*3])
            with open(e+'.csv','wb') as outfile:
                outfile.writelines(str(result)+'\n'+str(listCodon))

我的问题是生成的文件如下所示：

 0      0      0        
'GCA'  'CTT'   'GGT'

我想让它像这样：

0  GCA    
0  CTT    
0  GGT

我可以在我的代码中做些什么来实现这一点？

打印结果：

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3, 1, 2, 0, 0, 0, 0, 1, 0, 1, 1, 0, 1, 3, 3, 0, 3, 1, 2, 1, 2, 1, 0, 1, 0, 1, 2, 1, 0, 5, 0, 0, 0, 0, 6, 0, 1, 0, 0, 2, 0, 1, 0, 0, 1, 1, 0, 1, 6, 34, 35, 32, 1, 1, 0, 4, 1, 0, 1, 0, 0, 0, 0, 1, 6, 0, 0, 0, 0, 1, 3, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

打印列表密码子：

['gtt', 'gaa', 'aca', 'gag', 'aca', 'tgt', 'tct', 'gga', 'gat', 'gag', 'ctg', 'tgg', 'gca', 'gaa', 'gga', 'cag', 'gcc', 'taa', 'gca', 'cag', 'gca', 'gca', 'gag', 'ctt', 'tga', 'tct', 'ctt', 'ggt', 'gat', 'cgg', 'tgg', 'ggg', 'atc', 'cgg', 'tgg', 'cct', 'agc', 'ttg', 'tgc', 'caa', 'gga', 'agc', 'tgc', 'tca', 'gct', 'ggg', 'aaa', 'gaa', 'ggt', 'ggc', 'tgt', 'ggc', 'tga', 'cta', 'tgt', 'gga', 'acc', 'ttc', 'tcc', 'ccg', 'agg', 'cac', 'caa', 'gtg', 'ggg', 'cct', 'tgg', 'tgg', 'cac', 'ctg', 'tgt', 'caa', 'cgt', 'ggg', 'ttg', 'cat', 'acc', 'caa', 'gaa', 'gct', 'gat', 'gca', 'tca', 'ggc', 'tgc', 'act', 'gct', 'ggg', 'ggg', 'cat', 'gat', 'cag', 'aga', 'tgc', 'tca', 'cca', 'cta', 'tgg', 'ctg', 'gga', 'ggt', 'ggc', 'cca', 'gcc', 'tgt', 'cca', 'aca', 'caa', 'ctg', 'gtg', 'aga', 'gag', 'aag', 'ccc', 'ttg', 'ccc', 'tct', 'gca', 'ggt', 'ccc', 'att', 'gaa', 'agg', 'aga', 'ggt', 'ttg', 'ctc', 'tct', 'gcc', 'act', 'cat', 'ctg', 'taa', 'ccg', 'tga', 'gct', 'ttt', 'cca', 'ccc', 'ggc', 'ctc', 'ctc', 'ttt', 'gat', 'ccc', 'aga', 'ata', 'atg', 'act', 'ctg', 'aga', 'ctt', 'ctt', 'atg', 'tat', 'gaa', 'taa', 'atg', 'cct', 'ggg', 'cca', 'aaa', 'acc']

这就是 Marek 的代码帮助我实现的 这是我所希望的

左边的图片是 Marek 的代码帮助我实现的，我想做出改进，所以它像右边的图片一样排列

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2 回答 2

4

您可以使用zip()将两个迭代器压缩在一起。所以如果你有

result = [0, 0, 0, 0, 0]
listCodons = ['gtt', 'gaa', 'aca', 'gag', 'aca']

那么你可以做

>>> list(zip(result, listCodons))
[(0, 'gtt'), (0, 'gaa'), (0, 'aca'), (0, 'gag'), (0, 'aca')]

或者，对于您的示例：

with open(e+'.csv','w') as outfile:
    out = csv.writer(outfile)
    out.writerows(zip(result, listCodons))
于 2012-08-02T10:34:24.177 回答
1

试试这个：

proper_result = '\n'.join([ '%s %s' % (nr, codon)  for nr, codon  in zip(result, listCodon) ] )

编辑（密码子分成不同的列）：

proper_result = '\n'.join(' '.join([str(nr),] + list(codon))  for nr, codon  in zip(nrs, cdns))

编辑（逗号分隔值）：

proper_result = '\n'.join('%s, %s' % (nr, codon) for nr, codon in zip(result, listCodon))
于 2012-08-02T09:59:37.490 回答