php - 如何将项目添加到关联数组？

Question

我定义了我的数组

$data = array();

添加了 1 项：

$data['response'] = true;

现在我想一次添加多个项目，例如：

$data["picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2];

但我收到了这个错误：

parse error, expecting `']''

我究竟做错了什么？

score 5 · Accepted Answer

您可以将其写成多行，例如：

$data['new0'] = 'value0';
$data['new1'] = 'value1';

或使用array_merge（将覆盖碰撞键）：

$data = array_merge($data, array('new0' => 'value0', 'new1' => 'value1'));

score 3 · Accepted Answer

需要一一添加，或者使用array_merge方法。

$data["picUpload"] =$pPicUpload;
$data["Album1"] = $Album1;
$data["Album2"] = $Album2;

score 2 · Accepted Answer

您使用的语法不正确。您需要使用 array_merge 功能

$data = array_merge($data, array(
  "picUpload" => $pPicUpload, 
  "Album1" => $Album1, 
  "Album2" => $Album2
));

score 2 · Accepted Answer

$data = array_merge($data, Array("picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2));

score 1 · Accepted Answer

为什么不只是：

$data["picUpload"] = $pPicUpload;
$data["Album1"] = $Album1;
$data["Album2"] = $Album2;

score 0 · Accepted Answer

试试这个：

$data = array("picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2);

score 0 · Accepted Answer

试试这个，

$data = array("picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2);

7 回答 7