我目前正在创建一个 Twitter 客户端,作为学习为 Blackberry 10 开发的一种方式。我目前正在尝试为自定义 ListView 项创建一个上下文菜单,在选择时将在主布局中显示一个对话框。但是,我无法让选定的列表项从父页面调用任何函数。
这是我的自定义列表项中的 QML:
import bb.cascades 1.0
Container {
property alias avatar: tracker.imageSource
property alias username: txtTweetUser.text
property alias tweetText: txtTweetContent.text
property alias tweetTime: txtTweetTime.text
signal sendReply(string username)
function cout(text) {
console.debug("[DEBUG] " + text);
}
id: itemTweet
preferredWidth: 768;
preferredHeight: 200
// Actions
contextActions: [
ActionSet {
title: "Action Set"
subtitle: "This is an action set."
actions: [
ActionItem {
title: "Reply"
imageSource: "asset:///reply.png"
onTriggered: {
itemTweet.sendReply(txtTweetUser.text);
}
},
ActionItem {
title: "Retweet"
imageSource: "asset:///retweet.png"
},
ActionItem {
title: "Favourite"
imageSource: "asset:///fav.png"
}
]
} // end of ActionSet
] // end of contextActions list
<Layout for the List Item>...
}
}
对于主 QML 文件:
import bb.cascades 1.0
TabbedPane {
id: tabbedPane
showTabsOnActionBar: true
Tab {
id: tabTimeline
title: "Timeline"
imageSource: "asset:///twitter-white.png"
Page {
id: pageTimeline
signal openReply
signal showNewTweet
function cout(text) {
console.debug("[DEBUG] " + text);
}
function showTweetWindow(username) {
pageTimeline.dialogNewTweet.text = username;
pageTimeline.dialogNewTweet.visible = true;
}
// Title bar
titleBar: TitleBar {
visibility: Overlay
title: "Twitter"
acceptAction: ActionItem {
id: btnNewTweet
title: "+"
ActionBar.placement: ActionBarPlacement.OnBar
onTriggered: {
pageTimeline.cout("action selected");
dialogNewTweet.visible = true;
}
}
}
// Main content
content: Container {
layout: AbsoluteLayout {}
Container {
// Listview for the tweets
ListView {
id: lstTweets
objectName: "lstTweets"
// Components to display the rows
listItemComponents: [
ListItemComponent {
id: listItem
type: "listItem"
TweetItem {
tweetText: ListItemData.content
tweetTime: ListItemData.time
avatar: ListItemData.avatar
username: ListItemData.username
onSendReply: {
cout("Reply selected in parent to " + username);
pageTimeline.showTweetWindow(username);
}
}
}
]
onSelectionChanged: {
}
function itemType(data, indexPath) {
if (indexPath.length == 1) {
return "header";
} else {
return "listItem";
}
}
}
}
DialogNewTweet {
id: dialogNewTweet
visible: false
onShowNewTweet: {
dialogNewTweet.visible = true;
}
}
}
// End container
}
}
... <Other tabs> ...
}
因此,当主 QML 文件接收到 SendReply 信号时,应该调用showTweetWindow(username)
它然后使其dialogNewTweet
可见,但我得到了错误ReferenceError: Can't find variable: pageTimeline
。这绝对是一个范围问题,但我无法弄清楚我做错了什么,或者我是否需要重组它。