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在我的拖放文字游戏中，设置的网格大小为 6x6（36 个单元格）。它由 6 个 3 个字母的单词和 18 个空格组成。

目前网格是每行 2 个单词，当我在列表中添加一个长于 3 个字母的单词时，当该行上有另一个单词时，它会与网格重叠。

我需要一些脚本，可以为大于 3 个字母的单词赋予它们自己的行，这样网格就不会重叠。

有人可以给我一些建议吗？

这是从 HTML 中的数组列表创建表的脚本...

var listOfWords = [];
var rndWord = [];
var ul = document.getElementById("wordlist");

var i;
for (i = 0; i < ul.children.length; ++i) {

    listOfWords.push({
        "name": ul.children[i].getAttribute("data-word"),
        "pic": ul.children[i].getAttribute("data-pic"),
        "audio": ul.children[i].getAttribute("data-audio")
    });

    console.log(listOfWords);
    }

    console.log(listOfWords);

var chosenWords = [];
var cpy_list = listOfWords.slice();

for (var x = 0; x < 6; x++) {
    var rand = Math.floor(Math.random() * (cpy_list.length));
    console.log('push ' + cpy_list[rand].name);
    chosenWords.push(cpy_list[rand].name);
    cpy_list.splice(rand, 1);
    console.log(cpy_list);
        if (chosenWords.length < 12) {
        console.log('make a blank');
        chosenWords.push('   ');
    }
}

console.log(chosenWords);
var shuffledWords = [];
shuffledWords = chosenWords.sort(function() {
    return 0.5 - Math.random()
});

var guesses = {};
console.log(shuffledWords);
var tbl = document.createElement('table');
tbl.className = 'tablestyle';
var wordsPerRow = 2;

for (var i = 0; i < shuffledWords.length - 1; i += wordsPerRow) {

    var row = document.createElement('tr');
    console.log(shuffledWords);
    for (var j = i; j < i + wordsPerRow; ++j) {
        var word = shuffledWords[j];
        console.log(j);
        console.log(word);
        guesses[word] = [];

        for (var k = 0; k < word.length; ++k) {
            var cell = document.createElement('td');


            $(cell).addClass('drop').attr('data-word', word);
            cell.textContent = word[k];

            row.appendChild(cell);
        }
    }
    tbl.appendChild(row);
}
document.body.appendChild(tbl);

这是 HTML 中的单词列表...

<ul style="display:none;" id="wordlist">

    <li data-word="mum" data-audio="http://www.wav-sounds.com/cartoon/daffyduck1.wav" data-pic="http://www.clker.com/cliparts/5/e/7/f/1195445022768793934Gerald_G_Lady_Face_Cartoon_1.svg.med.png"></li>

    <li data-word="cat" data-audio="http://www.wav-sounds.com/cartoon/porkypig1.wav" data-pic="http://www.clker.com/cliparts/c/9/9/5/119543969236915703Gerald_G_Cartoon_Cat_Face.svg.med.png"></li>

    <li data-word="dog" data-audio="http://www.wav-sounds.com/cartoon/porkypig1.wav" data-pic="http://www.clker.com/cliparts/e/9/4/1/1195440435939167766Gerald_G_Dog_Face_Cartoon_-_World_Label_1.svg.med.png"></li>

    <li data-word="bug" data-audio="http://www.wav-sounds.com/cartoon/porkypig1.wav" data-pic="http://www.clker.com/cliparts/4/b/4/2/1216180545881311858laurent_scarabe.svg.med.png"></li>

    <li data-word="rat" data-audio="http://www.wav-sounds.com/cartoon/daffyduck1.wav" data-pic="http://www.clker.com/cliparts/C/j/X/e/k/D/mouse-md.png"></li>

    <li data-word="dad" data-audio="http://www.wav-sounds.com/cartoon/daffyduck1.wav" data-pic="http://www.clker.com/cliparts/H/I/n/C/p/Z/bald-man-face-with-a-mustache-md.png"></li>

    <li data-word="cop" data-audio="http://www.wav-sounds.com/cartoon/daffyduck1.wav" data-pic="http://www.clker.com/cliparts/1/4/c/5/1194984609285255522police_man_ganson.svg.med.png"></li>

    <li data-word="pig" data-audio="http://www.wav-sounds.com/cartoon/porkypig1.wav" data-pic="http://www.clker.com/cliparts/6/c/c/c/13286504431247546768Simple%20Pig%20Cartoon.svg.med.png"></li>

    <li data-word="sun" data-audio="http://www.wav-sounds.com/cartoon/porkypig1.wav" data-pic="http://www.clker.com/cliparts/3/b/1/2/11971486551534036964ivak_Decorative_Sun.svg.med.png"></li>

    <li data-word="kid" data-audio="http://www.wav-sounds.com/cartoon/daffyduck1.wav" data-pic="http://www.clker.com/cliparts/d/9/9/f/11954449391541537067Gerald_G_Girl_Face_Cartoon.svg.med.png"></li>
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1 回答 1

0

试试这个，让我知道它是否有帮助......

var listOfWords = [];
var rndWord = [];
var counter = 0;
var ul = document.getElementById("wordlist");
var i;

for (i = 0; i < ul.children.length; ++i) {

    listOfWords.push({
        "name": ul.children[i].getAttribute("data-word"),
        "pic": ul.children[i].getAttribute("data-pic"),
        "audio": ul.children[i].getAttribute("data-audio")
    });
}

var chosenWords = [];
var copylist = listOfWords.slice();

for (var x = 0; x < 6; x++) {
    var rand = Math.floor(Math.random() * (copylist.length));
    chosenWords.push(copylist[rand].name);
    copylist.splice(rand, 1);
    if (chosenWords.length < 12) {
        chosenWords.push('   ');
    }

}

var shuffledWords = [];
shuffledWords = chosenWords.sort(function() {
    return 0.5 - Math.random()
});

var guesses = {};
var tbl = document.createElement('table');
tbl.className = 'tablestyle';
var wordsPerRow = 2;

for (var i = 0; i < shuffledWords.length - 1; i += wordsPerRow) {

    var row = document.createElement('tr');
    for (var j = i; j < i + wordsPerRow; ++j) {
        var word = shuffledWords[j];
        guesses[word] = [];

        for (var k = 0; k < word.length; ++k) {
            var cell = document.createElement('td');


            $(cell).addClass('drop-box').attr('data-word', word).attr('data-letter', word[k]);
            cell.textContent = word[k];

            row.appendChild(cell);
        }
    }

    tbl.appendChild(row);
}

$(".container").append(tbl);
于 2012-08-20T08:03:42.320 回答