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我试图在 Java 中创建一个 XMPP 测试客户端,我想插入我的代码,它的行为就像真正的 xmpp 客户端,但会输出消息,例如到日志中。我的目标是这样做,因为我想在现实的环境中或接近的环境中进行测试。

理想情况下,我不想模拟或存根它,因为我希望运行 xmpp 客户端。

有任何想法吗?

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2 回答 2

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你遇到过Psi吗?它是一个非常强大的跨平台 XMPP 客户端,让您可以在其控制台中查看原始 XMPP 流以及粘贴您自己的 XML 以直接发送。它可以节省您编写自己的基于 Smack 的 XMPP 客户端的时间。也看看我听到的相似的gajim 。

于 2012-08-01T16:12:09.973 回答
0

这将帮助您在 xmpp 上向接收者发送消息。请记住,在运行此之前,您必须配置 openfire

import org.jivesoftware.smack.Chat;
import org.jivesoftware.smack.ChatManager;
import org.jivesoftware.smack.ConnectionConfiguration;
import org.jivesoftware.smack.MessageListener;
import org.jivesoftware.smack.XMPPConnection;
import org.jivesoftware.smack.XMPPException;
import org.jivesoftware.smack.packet.Message;
import org.jivesoftware.smack.packet.Presence;

public class SenderTest 
{
public static void main(String args[])
{
    //ConnectionConfiguration connConfig = new ConnectionConfiguration("localhost", 5222);
        //connConfig.setSASLAuthenticationEnabled(false);
     ConnectionConfiguration connConfig = new ConnectionConfiguration("localhost", 5222);
     //ConnectionConfiguration connConfig = new ConnectionConfiguration("talk.google.com", 5222, "gmail.com");
       XMPPConnection connection = new XMPPConnection(connConfig);

        try {
            connection.connect();
            System.out.println("Connected to " + connection.getHost());
        } catch (XMPPException ex) {
            //ex.printStackTrace();
            System.out.println("Failed to connect to " + connection.getHost());
            System.exit(1);
        }
        try {
            connection.login("sender@example.com", "a");
            System.out.println("Logged in as " + connection.getUser());

            Presence presence = new Presence(Presence.Type.available);
            connection.sendPacket(presence);

        } catch (XMPPException ex) {
            //ex.printStackTrace();
            System.out.println("Failed to log in as " + connection.getUser());
            System.exit(1);
        }

    ChatManager chatmanager = connection.getChatManager();
    Chat newChat = chatmanager.createChat("receiver@gmail.com", new MessageListener() {
        public void processMessage(Chat chat, Message message) {
            System.out.println("Received message: " + message);
        }
    });

    try {
        newChat.sendMessage("Howdy!");
        System.out.println("Message Sent...");
    }
    catch (XMPPException e) {
        System.out.println("Error Delivering block");
    }
}

}
于 2012-08-07T08:52:31.883 回答