我正在尝试使用 Beautiful Soup 在 ajax 页面上抓取表格,并使用 TextTable 库以表格形式将其打印出来。
import BeautifulSoup
import urllib
import urllib2
import getpass
import cookielib
import texttable
cj = cookielib.CookieJar()
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj))
urllib2.install_opener(opener)
...
def show_queue():
url = 'https://www.animenfo.com/radio/nowplaying.php'
values = {'ajax' : 'true', 'mod' : 'queue'}
data = urllib.urlencode(values)
f = opener.open(url, data)
soup = BeautifulSoup.BeautifulSoup(f)
stable = soup.find('table')
table = texttable.Texttable()
header = stable.findAll('th')
header_text = []
for th in header:
header_append = th.find(text=True)
header.append(header_append)
table.header(header_text)
rows = stable.find('tr')
for tr in rows:
cells = []
cols = tr.find('td')
for td in cols:
cells_append = td.find(text=True)
cells.append(cells_append)
table.add_row(cells)
s = table.draw
print s
...
虽然我试图抓取的相关 HTML 的 URL 显示在代码中,但这里有一个示例:
<table cellspacing="0" cellpadding="0">
<tbody>
<tr>
<th>Artist - Title</th>
<th>Album</th>
<th>Album Type</th>
<th>Series</th>
<th>Duration</th>
<th>Type of Play</th>
<th>
<span title="...">Time to play</span>
</th>
</tr>
<tr>
<td class="row1">
<a href="..." class="songinfo">Song 1</a>
</td>
<td class="row1">
<a href="..." class="album_link">Album 1</a>
</td>
<td class="row1">...</td>
<td class="row1">
</td>
<td class="row1" style="text-align: center">
5:43
</td>
<td class="row1" style="padding-left: 5px; text-align: center">
S.A.M.
</td>
<td class="row1" style="text-align: center">
~0:00:00
</td>
</tr>
<tr>
<td class="row2">
<a href="..." class="songinfo">Song2</a>
</td>
<td class="row2">
<a href="..." class="album_link">Album 2</a>
</td>
<td class="row2">...</td>
<td class="row2">
</td>
<td class="row2" style="text-align: center">
6:16
</td>
<td class="row2" style="padding-left: 5px; text-align: center">
S.A.M.
</td>
<td class="row2" style="text-align: center">
~0:05:43
</td>
</tr>
<tr>
<td class="row1">
<a href="..." class="songinfo">Song 3</a>
</td>
<td class="row1">
<a href="..." class="album_link">Album 3</a>
</td>
<td class="row1">...</td>
<td class="row1">
</td>
<td class="row1" style="text-align: center">
4:13
</td>
<td class="row1" style="padding-left: 5px; text-align: center">
S.A.M.
</td>
<td class="row1" style="text-align: center">
~0:11:59
</td>
</tr>
<tr>
<td class="row2">
<a href="..." class="songinfo">Song 4</a>
</td>
<td class="row2">
<a href="..." class="album_link">Album 4</a>
</td>
<td class="row2">...</td>
<td class="row2">
</td>
<td class="row2" style="text-align: center">
5:34
</td>
<td class="row2" style="padding-left: 5px; text-align: center">
S.A.M.
</td>
<td class="row2" style="text-align: center">
~0:16:12
</td>
</tr>
<tr>
<td class="row1"><a href="..." class="songinfo">Song 5</a>
</td>
<td class="row1">
<a href="..." class="album_link">Album 5</a>
</td>
<td class="row1">...</td>
<td class="row1"></td>
<td class="row1" style="text-align: center">
4:23
</td>
<td class="row1" style="padding-left: 5px; text-align: center">
S.A.M.
</td>
<td class="row1" style="text-align: center">
~0:21:46
</td>
</tr>
<tr>
<td style="height: 5px;">
</td></tr>
<tr>
<td class="row2" style="font-style: italic; text-align: center;" colspan="5">There are x songs in the queue with a total length of x:y:z.</td>
</tr>
</tbody>
</table>
每当我尝试运行此脚本函数时,它都会以TypeError: find() takes no keyword arguments
on中止header_append = th.find(text=True)
。我有点难过,因为似乎我正在做代码示例中显示的事情,而且它似乎应该工作,但它没有。
简而言之,我该如何修复代码以便没有 TypeError 以及我做错了什么?
编辑:我在编写脚本时提到的文章和文档: