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我制作了自己的模块来将 php 表单的数据提交到数据库中。我现在有一篇文章里面的模块。

当我提交表单时，即使我有另一个模板页面可以成功提交，它也会进入 404 错误页面。

我曾尝试使用 action = post.php 以及确切的 URL，但它失败了。

有谁知道我出了什么问题？

这是网址：http ://aubrey-joomla-test.freeiz.com/index.php/new-user-registration-form

这是我的默认模板的文件名：default_tmpl.php

这是我的 tmpl 代码：

<div>
    <form action="<?php echo JRoute::_('index.php'); ?>" method="post" id="myform" class="cols"  >

        <input type="hidden" name="form_send" value="send" />

        <h2>New User Registration Form</h2>
                <table>
                <label>Are you employed?</label>
                <tr>
                    <td><label><input type="radio" name="option" value="1" required="required">Yes</label></td>
                    <td><label><input type="radio" name="option" value="0" required="required">No</label></td>
                </tr>
                <label>If not, please proceed to the next section.</label>
                </table>

          <fieldset name="salary">

            <h4>Income From Employment</h4>             
                <table> <tr><label>Pay cycle:</label>
                    <td><label><input type="radio" name="option1" value="1" required="required">Monthly</label></td>
                    <td><label><input type="radio" name="option1" value="2" required="required">Biweekly</label></td>
                </tr> </table>
            <p><label>Please enter your typical pay: <input type="text" name="amountpay" required="required" pattern="\d+(\.\d{2})?"/> </label></p>
            <p><label>Please select your next pay day: <input type="date" name="paydate"  required="required" /> </label></p>

          </fieldset>

          <fieldset name="fixeditems">
            <h4>Fixed Items</h4>
                <table> <label>Payment cycle:</label> <tr>
                <td><label><input type="radio" name="option2" value="1" required="required">Monthly</label></td>
                <td><label><input type="radio" name="option2" value="2" required="required">Biweekly</label></td>
                <tr>
                </table>

                <table> <label>Is this a form of:</label> <tr>
                    <td><label><input type="radio" name="option3" value="2" required="required">Income</label></td>
                    <td><label><input type="radio" name="option3" value="1" required="required">Expense</label></td>
                <tr>
                </table>        

            <p><label>Please enter the typical amount: <input type="text" name="amount" required="required" pattern ="\d+(\.\d{2})?" /> </label></p>
            <p><label>Please select the next due date: <input type="date"  name="amountdate" required="required" /> </label></p>
          </fieldset>

          <hr>

          <div class="clear"></div>

          <button type="submit" name="send" value="Send">Submit form</button>
          <button type="reset">Reset</button>



</form>
</div>
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1 回答 1

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You have no code to handle a form submission. You need to add in a hidden field that would trigger additional code that handles the form submission instead of displaying the form. You need something like this in your module -

if $_POST["form_submit_trigger"] :

PUT SOME CODE HERE TO HANDLE YOUR SUBMITTED DATA

else

PUT THE CODE TO DISPLAY YOUR FORM HERE

form_submit_trigger should be a hidden field in your form that is generated and hashed each time the form is diaplyed. This way you can confirm that the form was actually generated and submitted on your site.

于 2012-08-09T14:48:24.243 回答