php - 解析 Skype 日志

Question

我需要解析 Skype 日志，获取所有通话时长并将它们相加，然后找出整个聊天记录的通话总时长。

样本：

[3/12/2012 11:36:44 AM] * 通话结束，持续时间 21:33 *

我想我需要将 preg_match 与正确的正则表达式一起使用。如果可以同时将实际时间戳存储在数组中，那就更好了。

我认为我真正难过的是获取通话时间所需的实际正则表达式规则。

Answer 1

尝试这个

(?i)\[(?P<time_stamp>[^[]+)\]\s*[*]\s*[a-z ,]+(?P<duration>(?:\d{2}:?){2,3})\s*[*]

解释

"
(?i)               # Match the remainder of the regex with the options: case insensitive (i)
\[                 # Match the character “[” literally
(?P<time_stamp>    # Match the regular expression below and capture its match into backreference with name “time_stamp”
   [^[]               # Match any character that is NOT a “[”
      +                  # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
\]                 # Match the character “]” literally
\s                 # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
   *                  # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
[*]                # Match the character “*”
\s                 # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
   *                  # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
[a-z ,]            # Match a single character present in the list below
                      # A character in the range between “a” and “z”
                      # One of the characters “ ,”
   +                  # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(?P<duration>      # Match the regular expression below and capture its match into backreference with name “duration”
   (?:                # Match the regular expression below
      \d                 # Match a single digit 0..9
         {2}                # Exactly 2 times
      :                  # Match the character “:” literally
         ?                  # Between zero and one times, as many times as possible, giving back as needed (greedy)
   ){2,3}             # Between 2 and 3 times, as many times as possible, giving back as needed (greedy)
)
\s                 # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
   *                  # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
[*]                # Match the character “*”
"

Answer 2

你可以使用这个：

 \*.+?([0-9]+:){1,2}([0-9]+)

然后它可以捕获第一个之后的 HH:MM:SS 和 MM:SS *。