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我有一个用户表，我需要在其中运行报告并显示给定年份每个月用户进入系统的次数。我创建了一个表，其中第一列返回不同的用户。接下来，在右侧，我想显示每个月用户输入了多少次。我目前拥有的代码只计算每个月的总数，并将每个月的总数放入所有用户。在下面的案例中，它为每个用户列出了 5 月的 7 个、6 月的 13 个和 7 月的 12 个。但我希望它显示如下，它按月分解。

Users    May    June    July  
User1     1       2       3     
User2     1       1       2  
User3     5       10      7   

<?php
$sql = "SELECT record,count(*) as TotalCount,

(select DISTINCT count(*) from Table1 WHERE datereceived BETWEEN '2012-05-01' AND '2012-05-31') as May,
(select DISTINCT count(*) from Table1 WHERE datereceived BETWEEN '2012-06-01' AND '2012-06-30') as June,
(select DISTINCT count(*) from Table1 WHERE datereceived BETWEEN '2012-07-01' AND '2012-07-31') as July
FROM Table1 GROUP BY record";
$params = array();
$options =  array( "Scrollable" => SQLSRV_CURSOR_KEYSET );
$stmt = sqlsrv_query( $conn, $sql ,  $params, $options );
if( $stmt === false)
{
echo "Error in query preparation/execution.\n";
die( print_r( sqlsrv_errors(), true));
}
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC)) { 
?>  

<tr id="styling">
    <td class="style"><?php echo $row['record']; ?></td>
    <td class="style"><?php echo $row['May']; ?></td>
    <td class="style"><?php echo $row['June']; ?></td>
    <td class="style"><?php echo $row['July']; ?></td>
</tr>
<?php } ?>
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2 回答 2

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嗨，你可以试试这个

按名字从用户组中选择不同的fitstname，datename（month，datereceived），count（*），datename（month，datereceived）

于 2012-07-31T21:19:55.047 回答
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我认为最好按您的日期字段分组，而不是您现在如何使用它。

select DISTINCT count(*) from Table1 GROUP BY EXTRACT(MONTH FROM datereceived)

但我看不到您使用哪个字段来识别用户。您也可以尝试在该领域进行分组。

于 2012-07-31T21:15:49.287 回答