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我正在尝试将 addListeners 分配给有多个标记但不起作用的单个标记。发生的事情是所有的窗口都同时打开，即使我没有点击。当我点击时，什么也没有发生。怎么了？

这是我的代码：

<script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?key=AIzaSyDUE08r9kD1p5QsqOzmI6_EcoUNCJntf5I&sensor=false"></script>
<script type="text/javascript">

    //start the map. code from google maps tutorial.
    function initialize() { 
        var mapOptions = {
          center: new google.maps.LatLng(37.7750, -122.4183),
          zoom: 11,
          mapTypeId: google.maps.MapTypeId.ROADMAP
        };

        //return a map for later use
        return new google.maps.Map(document.getElementById("map_canvas"),
            mapOptions); 
    }

    function request() {
        $.ajax ({
            type: "GET",
            dataType: "json",
            url: "stations.php",
            data: {
                route: $("#route").val()
            },
            success: function(data) {
                var routePathCoords = [];
                var pathColor = data.color; 

                $.each(data.stations, function(i,j) {
                    routePathCoords.push(new google.maps.LatLng(data.lat[i], data.longit[i]));

                });

                //create new map
                var map = initialize();

                //generating the polyline
                var routePath = new google.maps.Polyline({ 
                    path: routePathCoords,
                    strokeColor: pathColor,
                    strokeOpacity: 1.0,
                    strokeWeight: 5
                });

                routePath.setMap(map);

                //creating each marker, display on screen
                $.each(routePathCoords, function(i,c) {
                    var marker = new google.maps.Marker({
                        //obtaining from coordinates array
                        position: c, 
                        map: map,
                        //obtaining from stations array
                        title: data.stations[i] 
                    });

                    var name = marker.title;
                    //listen for click, then activate window
                    google.maps.event.addListener(marker, 'click', stnWindow(name, marker, map));

                });

            },
            error:function (xhr, ajaxOptions, thrownError){
                    console.log(ajaxOptions);
                    alert(xhr.status);
                    alert(thrownError);
                }    
        });
        return false;
    }

    function stnWindow(name, marker, map) {

        $.ajax({
            type: "GET",
            dataType: "json",
            url: "window.php",
            data: {
                name: name
            },
            success: function(data) {
                //initializing variables for window+content
                var station = data.fullname;
                var infoWindow = new google.maps.InfoWindow;
                //adding station title
                var content = "<h1>" + station + "</h1>";
                //get names and times, put into var content
                $.each(data.destns, function(i,n) {
                    content = content + "<h2> Destination: </h2>" + n;
                    content = content + "<h3> Arrival: </h3>" + data.arrivals[i] + "minutes" ;

                });
                infoWindow.setContent(content);
                infoWindow.open(map, marker);
            }
        })
    }
</script>

<script type="text/javascript">



</script>
4

2 回答 2

1

您正在执行该stnWindow功能而不是分配它。

您可以通过返回仅包含 ajax 调用的函数来解决它，如下所示：

function stnWindow (name, marker, map) {
  return function () {
    $.ajax() //...
  }
}

在触发点击之前，这不会触发返回的函数。

于 2012-07-31T20:35:52.207 回答
0 
Try to replace :   
 google.maps.event.addListener(marker, 'click', stnWindow(name, marker, map));  
by :  
 google.maps.event.addListener(marker, 'click', function(){  
  $.ajax({  
        type: "GET",  
        dataType: "json",  
        url: "window.php",  
        data: {  
            name: name  
        },  
        success: function(data) {  
            //initializing variables for window+content  
            var station = data.fullname;  
            ....
            infoWindow.open(map, marker);
        }  
    })  
});
于 2012-07-31T20:41:41.767 回答