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我正在使用 Restkit 的 RKObjectManager 和 RKObjectMapping 使用 GET 从 Web 服务中成功检索 JSON 数据。这是我的代码：

- (void)viewDidLoad
{
    [super viewDidLoad];

    RKURL *baseURL = [RKURL URLWithBaseURLString:@"http://192.168.1.12"];
    RKObjectManager *objectManager = [RKObjectManager objectManagerWithBaseURL:baseURL];
    objectManager.client.baseURL = baseURL;

    RKObjectMapping *markerMapping = [RKObjectMapping mappingForClass:[Marker class]];
    [markerMapping mapKeyPath:@"la" toAttribute:@"lat"];
    [markerMapping mapKeyPath:@"lo" toAttribute:@"lon"];
    [markerMapping mapKeyPath:@"des" toAttribute:@"description"];
    [objectManager.mappingProvider setMapping:markerMapping forKeyPath:@"markers"];
}

- (void)sendGet
{
    NSString *lat = @"53.334932";
    NSString *lon = @"-0.543749";
    NSString *dist = @"1000";

    NSDictionary *queryParams;
    queryParams = [NSDictionary dictionaryWithObjectsAndKeys:lat, @"la", lon, @"lo", dist, @"d", nil];
    RKObjectManager *objectManager = [RKObjectManager sharedManager];

    RKURL *URL = [RKURL URLWithBaseURL:[objectManager baseURL] resourcePath:@"/get_markers.php" queryParameters:queryParams];
    [objectManager loadObjectsAtResourcePath:[NSString stringWithFormat:@"%@?%@", [URL resourcePath], [URL query]] delegate:self];
}

上面的代码正在运行，我很高兴使用返回的数据。但是，我无法发布要插入数据库的记录。我想我可以重用 sharedManager 甚至可能是映射。我不需要处理任何退货。

我尝试了以下片段的多种变体。无济于事。

第一个片段是尝试重用管理器和映射。忽略此伪代码中的映射范围，明显的缺陷是我无法弄清楚如何发布到正确的 URL 资源（baseURL & '/insert_marker.php'）。所以我实际上没有尝试过这个：

- (void)postInsert
{  
    Marker *mkr = [Marker alloc];
    mkr.lat = @"53.334933";
    mkr.lon = @"-0.543750";
    mkr.description = @"some words";

    RKObjectManager *objectManager = [RKObjectManager sharedManager];
    [objectManager.mappingProvider setSerializationMapping:[markerMapping inverseMapping] forClass:[Marker class]];
    [[RKObjectManager objectManager] postObject:mkr delegate:nil];
}

第二个片段运行但应用程序崩溃。显然，这在字符串和 url 类型之间存在混淆，但对象管理器帖子不会使用 url 进行编译。我很迷茫！

- (void)postInsert
{  
    RKParams* params = [RKParams params];
    [params setValue:@"53.334933" forParam:@"la"];
    [params setValue:@"-0.543750" forParam:@"l0"];
    [params setValue:@"some words" forParam:@"des"];

    RKObjectManager *objectManager = [RKObjectManager sharedManager];
    NSString *URL = [RKURL URLWithBaseURL:[objectManager baseURL] resourcePath:@"/add_marker.php"];
    [objectManager.client post:URL params:params delegate:nil];
}

那么，我如何使用参数发布（希望重用 sharedManager，也许是映射而不是处理返回）？

4

1 回答 1

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如评论中所述，尝试使用 NSStrings 而不是 RKURL，如下所示：

NSString *baseUrl = @"https://mysite.com"; 
[RKObjectManager objectManagerWithBaseURLString:baseUrl];

如果你想让一些东西更健壮，你也可以尝试使用 objectManager 而不是 objectManager 上的客户端来发帖，例如你可以使用块：

- (void) post: (id) myEntity onLoad:(RKObjectLoaderDidLoadObjectBlock) loadBlock onError:(RKRequestDidFailLoadWithErrorBlock)failBlock showingLoader:(BOOL)loaderWillShow{

    RKObjectMapping *mapping = [[RKObjectManager sharedManager].mappingProvider objectMappingForClass:[[myEntity class] class]];
    [[RKObjectManager sharedManager] postObject:myEntity usingBlock:^(RKObjectLoader *loader) {
        [self settingsForLoader:loader withMapping:mapping onLoad:loadBlock onError:failBlock showingLoader:loaderWillShow];
    }];

}

//Settings For Loader definition:



- (void) settingsForLoader: (RKObjectLoader *) loader withMapping: (RKObjectMapping *) mapping onLoad:(RKObjectLoaderDidLoadObjectBlock) loadBlock onError:(RKRequestDidFailLoadWithErrorBlock)failBlock showingLoader:(BOOL) loaderWillShow{

    loader.objectMapping = mapping;
    loader.delegate = self;
    loader.onDidLoadObject = loadBlock;

    loader.onDidFailWithError = ^(NSError * error){
       //NSLog(@"%@",error);
    };

    loader.onDidFailLoadWithError = failBlock;
    loader.onDidLoadResponse = ^(RKResponse *response) {
        [self fireErrorBlock:failBlock onErrorInResponse:response disablingLoader:loaderWillShow];
    };

}
于 2012-07-31T18:23:26.860 回答