我有一个解析verilog连接的简单语法：
scalar = (Optional(Word(nums + "_") + "'" + oneOf("d h b")) + Word(nums + "_")).setName("Scalar")
operator = oneOf("+ - * /").setName("Operator")
identifier = Word(alphas, alphanums+"_").setName("Identifier")
expr = (scalar | identifier) + ZeroOrMore(operator + (scalar | identifier))
range = expr + ":" + expr
index = "[" + range + "]"
single_netref = (identifier + Optional(index)).setName("Single Net Reference")
single_netref.setDebug()
lbracket = Literal("{").setName("Left Bracket").setDebug()
rbracket = Literal("}").setName("Left Bracket").setDebug()
concat_netref = (lbracket + single_netref + ZeroOrMore( Suppress( "," ) + single_netref ) + rbracket).setName("Net Concatination Reference")
concat_netref.setDebug()
如果我使用 parseString 方法解析字符串“{ LegacyStatus3gPreStageQ1 , LegacyData3gPreStageQ1 }”，它解析得很好；但是，我想匹配网络引用的串联或单个网络引用。为此，我尝试过：
netref = MatchFirst(concat_netref, single_netref).setName("Net Reference").setDebug()
但是，这（并使用 Or()）总是跳过最后一个 rbracket，但表示它成功匹配了 netref。这是我的调试输出：
Match Net Reference at loc 0(1,1)
Match Left Bracket at loc 0(1,1)
Matched Left Bracket -> ['{']
Match Single Net Reference at loc 1(1,2)
Matched Single Net Reference -> ['LegacyStatus3gPreStageQ1']
Match Single Net Reference at loc 28(1,29)
Matched Single Net Reference -> ['LegacyData3gPreStageQ1']
Matched Net Reference -> ['{', 'LegacyStatus3gPreStageQ1', 'LegacyData3gPreStageQ1']
为什么添加 MatchFirst() 元素会导致 rbracket 丢失？