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有谁知道Progress 10.1C编码函数中使用了哪种算法?

我发现了这个: http: //knowledgebase.progress.com/articles/Article/21685

Progress 4GL ENCODE函数使用CRC -16算法生成其编码输出。

进度 4GL:

ENCODE("Test").

给出输出“ LkwidblanjsipkJC

但是例如在http://www.nitrxgen.net/hashgen/上使用密码“测试”,我从来没有从进度中得到结果。

有任何想法吗?:)

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5 回答 5

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我已经在https://github.com/pvginkel/ProgressEncode上提供了该算法。

于 2013-08-03T05:51:14.000 回答
2

我需要 Java 中的这个函数。所以我将 Pieter 的 C# 代码 ( https://github.com/pvginkel/ProgressEncode ) 移植到了 Java。至少所有测试用例都通过了。享受!:)

public class ProgressEncode {

    static int[] table = { 0x0000, 0xC0C1, 0xC181, 0x0140, 0xC301, 0x03C0,
            0x0280, 0xC241, 0xC601, 0x06C0, 0x0780, 0xC741, 0x0500, 0xC5C1,
            0xC481, 0x0440, 0xCC01, 0x0CC0, 0x0D80, 0xCD41, 0x0F00, 0xCFC1,
            0xCE81, 0x0E40, 0x0A00, 0xCAC1, 0xCB81, 0x0B40, 0xC901, 0x09C0,
            0x0880, 0xC841, 0xD801, 0x18C0, 0x1980, 0xD941, 0x1B00, 0xDBC1,
            0xDA81, 0x1A40, 0x1E00, 0xDEC1, 0xDF81, 0x1F40, 0xDD01, 0x1DC0,
            0x1C80, 0xDC41, 0x1400, 0xD4C1, 0xD581, 0x1540, 0xD701, 0x17C0,
            0x1680, 0xD641, 0xD201, 0x12C0, 0x1380, 0xD341, 0x1100, 0xD1C1,
            0xD081, 0x1040, 0xF001, 0x30C0, 0x3180, 0xF141, 0x3300, 0xF3C1,
            0xF281, 0x3240, 0x3600, 0xF6C1, 0xF781, 0x3740, 0xF501, 0x35C0,
            0x3480, 0xF441, 0x3C00, 0xFCC1, 0xFD81, 0x3D40, 0xFF01, 0x3FC0,
            0x3E80, 0xFE41, 0xFA01, 0x3AC0, 0x3B80, 0xFB41, 0x3900, 0xF9C1,
            0xF881, 0x3840, 0x2800, 0xE8C1, 0xE981, 0x2940, 0xEB01, 0x2BC0,
            0x2A80, 0xEA41, 0xEE01, 0x2EC0, 0x2F80, 0xEF41, 0x2D00, 0xEDC1,
            0xEC81, 0x2C40, 0xE401, 0x24C0, 0x2580, 0xE541, 0x2700, 0xE7C1,
            0xE681, 0x2640, 0x2200, 0xE2C1, 0xE381, 0x2340, 0xE101, 0x21C0,
            0x2080, 0xE041, 0xA001, 0x60C0, 0x6180, 0xA141, 0x6300, 0xA3C1,
            0xA281, 0x6240, 0x6600, 0xA6C1, 0xA781, 0x6740, 0xA501, 0x65C0,
            0x6480, 0xA441, 0x6C00, 0xACC1, 0xAD81, 0x6D40, 0xAF01, 0x6FC0,
            0x6E80, 0xAE41, 0xAA01, 0x6AC0, 0x6B80, 0xAB41, 0x6900, 0xA9C1,
            0xA881, 0x6840, 0x7800, 0xB8C1, 0xB981, 0x7940, 0xBB01, 0x7BC0,
            0x7A80, 0xBA41, 0xBE01, 0x7EC0, 0x7F80, 0xBF41, 0x7D00, 0xBDC1,
            0xBC81, 0x7C40, 0xB401, 0x74C0, 0x7580, 0xB541, 0x7700, 0xB7C1,
            0xB681, 0x7640, 0x7200, 0xB2C1, 0xB381, 0x7340, 0xB101, 0x71C0,
            0x7080, 0xB041, 0x5000, 0x90C1, 0x9181, 0x5140, 0x9301, 0x53C0,
            0x5280, 0x9241, 0x9601, 0x56C0, 0x5780, 0x9741, 0x5500, 0x95C1,
            0x9481, 0x5440, 0x9C01, 0x5CC0, 0x5D80, 0x9D41, 0x5F00, 0x9FC1,
            0x9E81, 0x5E40, 0x5A00, 0x9AC1, 0x9B81, 0x5B40, 0x9901, 0x59C0,
            0x5880, 0x9841, 0x8801, 0x48C0, 0x4980, 0x8941, 0x4B00, 0x8BC1,
            0x8A81, 0x4A40, 0x4E00, 0x8EC1, 0x8F81, 0x4F40, 0x8D01, 0x4DC0,
            0x4C80, 0x8C41, 0x4400, 0x84C1, 0x8581, 0x4540, 0x8701, 0x47C0,
            0x4680, 0x8641, 0x8201, 0x42C0, 0x4380, 0x8341, 0x4100, 0x81C1,
            0x8081, 0x4040 };

    public static byte[] Encode(byte[] input) {
        if (input == null)
            return null;
        byte[] scratch = new byte[16];
        int hash = 17;
        for (int i = 0; i < 5; i++) {
            for (int j = 0; j < input.length; j++)
                scratch[15 - (j % 16)] ^= input[j];
            for (int j = 0; j < 16; j += 2) {
                hash = Hash(scratch, hash);
                scratch[j] = (byte) (hash & 0xFF);
                scratch[j + 1] = (byte) ((hash >>> 8) & 0xFF);
            }
        }
        byte[] target = new byte[16];
        for (int i = 0; i < 16; i++) {
            byte lower = (byte) (scratch[i] & 0x7F);
            if ((lower >= 'A' && lower <= 'Z') || (lower >= 'a' && lower <= 'z'))
                target[i] = lower;
            else
                target[i] = (byte) (((scratch[i] >>> 4 & 0xF) + 0x61) & 0xFF);
        }
        return target;
    }

    private static int Hash(byte[] scratch, int hash) {
        for (int i = 15; i >= 0; i--)
            hash = ((hash >>> 8) & 0xFF ^ table[hash & 0xFF] ^ table[scratch[i] & 0xFF]) & 0xFFFF;
        return hash;
    }

}
于 2014-09-17T14:09:36.133 回答
1

CRC-16 有多种实现方式。Progress Software(故意)没有记录使用的变体。

你找这个的目的是什么?

于 2012-07-31T16:02:03.543 回答
1

我建议不要尝试使用“编码”,而是研究 OE 的加密功能。我不确定 10.1C 支持什么,我说 OE 支持的 11.0 文档:

• DES — Data Encryption Standard
• DES3 — Triple DES
• AES — Advanced Encryption Standard
• RC4 — Also known as ARC4

OE PDF 文档可在此处获得:http: //communities.progress.com/pcom/docs/DOC-16074

于 2012-08-02T20:30:03.533 回答
0

ENCODE 函数的工作方式只有一种。Progress 从未披露其背后的算法。另外,他们从未内置过解码功能。

与 OE 10.0B 一样,Progress 已在 ABL 中实施了密码学。看看 ENCRYPT 和 DECRYPT 函数。

于 2012-08-01T11:14:46.977 回答