0

我有两节课:

public class Code
{
    public virtual Guid CodeId { get; set; }
    public virtual string CodeValue { get; set; }
    public virtual Guid EntryId { get; set; }
}

public class Entry
{
    public virtual Guid EntryId { get; set; }
    public virtual string FirstName { get; set; }
    public virtual string LastName { get; set; }
    public virtual string Address { get; set; }
    public virtual string Address2 { get; set; }
    public virtual string City { get; set; }
    public virtual string State { get; set; }
    public virtual string Zip { get; set; }
    public virtual string Email { get; set; }
    public virtual string Phone { get; set; }
    public virtual string IpAddress { get; set; }
    public virtual DateTime BirthDate { get; set; }
    public virtual DateTime Created { get; set; }
    public virtual bool OptIn { get; set; }
    public virtual Code Code { get; set; }
}

我希望 nhibernate 自动加载/保存 Entry 对象的 Code 子属性(可以为 null,并由 Codes 表中的外键“EntryId”链接),但我无法弄清楚映射。hibernate.org 上的文档现在没有为我加载,所以有人可以用下面的映射为我指明正确的方向吗?

  <class name="Code" table="Codes">
    <id name="CodeId">
      <generator class="guid.comb"/>
    </id>
    <property name="CodeValue" />
    <property name="EntryId"
  </class>

  <class name="Entry" table="Entries">
    <id name="EntryId">
      <generator class="guid.comb"/>
    </id>
    <property name="FirstName" />
    <property name="LastName" />
    <property name="Address" />
    <property name="Address2" />
    <property name="City" />
    <property name="State" />
    <property name="Zip" />
    <property name="Email" />
    <property name="Phone" />
    <property name="BirthDate" />
    <property name="OptIn" />
    <property name="IpAddress" />
    <property name="Created" />    
  </class>
4

1 回答 1

0

我相信这篇文章很好地描述了这些可能性:http: //ayende.com/Blog/archive/2009/04/19/nhibernate-mapping-ltone-to-onegt.aspx

您只是不需要“模拟”双向性,但这很容易被忽略。

于 2009-07-24T07:14:14.667 回答