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我已经制作了这些代码来使用 TCP 套接字发送和接收图像,但接收代码不起作用。

这是发送代码

public void SendImage()
{
    int ScreenWidth = Screen.GetBounds(new Point(0, 0)).Width;
    int ScreenHeight = Screen.GetBounds(new Point(0, 0)).Height;
    Bitmap bmpScreenShot = new Bitmap(ScreenWidth, ScreenHeight);

    Graphics gfx = Graphics.FromImage((Image)bmpScreenShot);
    gfx.CopyFromScreen(0, 0, 0, 0, new Size(ScreenWidth, ScreenHeight));
    bmpScreenShot.Save(Application.StartupPath + "/ScreenShot.jpg", ImageFormat.Jpeg);
    byte[] image = new byte[1];
    bmpScreenShot = ResizeBitmap(bmpScreenShot, 300, 300);

    image = ImageToByte(bmpScreenShot);
    //get the length of image (length of bytes)
    int NumberOfBytes = image.Length;
    //put the size into a byte array
    byte[] numberofbytesArray = BitConverter.GetBytes(NumberOfBytes);

    //send the size to the Client
    int sizesend = sck.Send(numberofbytesArray, 0, numberofbytesArray.Length, 0);
    if (sizesend > 0)
    {
        MessageBox.Show("Size Sent");
    }
    //send the image to the Client
    int imagesend =sck.Send(image, 0, NumberOfBytes, 0);
    if (imagesend > 0)
    {
        MessageBox.Show("Image Sent");
    }
}

这是接收代码

public void ReceiveImage()
{
    if (sck.Connected)
    {
        {
            NetworkStream stream = new NetworkStream(sck);
            byte[] data = new byte[4];

            //Read The Size
            stream.Read(data, 0, data.Length);
            int size = (BitConverter.ToInt32(data,0));
            // prepare buffer
            data = new byte[size];

            //Load Image
            int read = 0;
            while (read != data.Length)
            {
               read += stream.Read(data, read, data.Length - read);
            }
            //stream.Read(data, 0, data.Length);
            //Convert Image Data To Image
            MemoryStream imagestream = new MemoryStream(data);
            Bitmap bmp = new Bitmap(imagestream);
            pictureBox1.Image = bmp;                    
        }
    }
}

问题是当我发送大小时,它以 5kb 的形式发送,但是当我收到它时,我发现它是 2GB 并且出现了这个错误:

无法从传输连接读取数据。由于系统缺少足够的缓冲区空间或队列已满,因此可能会在套接字上执行操作。

错误出现在此语句中read += stream.Read(data, read, data.Length - read);

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1 回答 1

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我会尝试获取更小的数据块。在您的代码中,您从所有数据开始(在失败的情况下一次 2GB。将其降低到更小的值 - 无论如何数据都是以块的形式发送的。例如:

read += stream.Read(buffer, read, 20480);

这将一次读取大约 2k,以免大于缓冲区空间或对于队列来说太大。

如果您分配了 2GB 大小的缓冲区,则您的应用程序可能只剩下很少的内存。底层框架可能无法为自己分配 2GB 的数据(总共分配了 4GB)来传输数据。

于 2012-07-31T13:32:51.903 回答