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当用户单击网格上的 RegionProjectName 字段时，我试图从查询字符串中传递网格的 RegionProjectID 列。我已将 RegionProjectname 作为超链接，您还可以在下面找到代码。但这不起作用。请建议我或帮助说明它为什么不起作用。在我的网格视图中也启用了分页。

<asp:GridView ID="ResultGridView" runat="server" AutoGenerateColumns="False" ShowFooter="true"
    DataKeyNames="RegionProjectID" 
    AllowPaging="True" 
    CellPadding="3" 
    OnPageIndexChanging="ResultGridView_PageIndexChanging" 
    OnRowDeleting="ResultGridView_RowDeleting" 
    CssClass="mGrid"
    OnRowEditing="ResultGridView_RowEditing" 
    OnRowUpdating="ResultGridView_RowUpdating" 
    OnRowCancelingEdit="ResultGridView_RowCancelingEdit" 
    PageSize="15" BackColor="#DEBA84" BorderColor="#DEBA84" BorderStyle="None" BorderWidth="1px" CellSpacing="2"
     OnRowCommand="ResultGridView_RowCommand" >
        <Columns>
            <asp:BoundField DataField="RegionProjectID" HeaderText="Region ID" InsertVisible="False"
                ReadOnly="True" SortExpression="RegionProjectID" Visible="false" />
            <asp:TemplateField HeaderText="Region Name" SortExpression="RegionProjectName">
                <EditItemTemplate>
                    <asp:TextBox ID="txtRegion" Width="250px" runat="server" Text='<%# Bind("RegionProjectName") %>'></asp:TextBox>
                </EditItemTemplate>
                <FooterTemplate>
                <asp:TextBox ID="txtRegion1" runat="server"  Width="250px"></asp:TextBox> 
                </FooterTemplate>
                <ItemTemplate>
                   <asp:LinkButton ID="LinkButton3" CommandName="Details" CommandArgument='<%# Eval("RegionProjectID") %>' Text='<%# Bind("RegionProjectName") %>' runat="server" /> 
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField HeaderText="Edit" ShowHeader="False"> 
            <EditItemTemplate> 
              <asp:LinkButton ID="LinkButton1" runat="server" CausesValidation="True" CommandName="Update" Text="Update"></asp:LinkButton> 
              <asp:LinkButton ID="LinkButton2" runat="server" CausesValidation="False" CommandName="Cancel" Text="Cancel"></asp:LinkButton> 
            </EditItemTemplate> 
            <FooterTemplate> 
              <asp:LinkButton ID="LinkButton2" runat="server" CausesValidation="False" CommandName="AddNew" Text="Add New"></asp:LinkButton> 
            </FooterTemplate> 
            <ItemTemplate> 
              <asp:LinkButton ID="LinkButton1" runat="server" CausesValidation="False" CommandName="Edit" Text="Edit"></asp:LinkButton> 
            </ItemTemplate> 
            </asp:TemplateField> 
            <asp:CommandField HeaderText="Delete" ShowDeleteButton="True"  ShowHeader="True" /> 
           <%-- <asp:CommandField HeaderText="Select" ShowSelectButton="True"  ShowHeader="True"/> --%>

        </Columns>
        <RowStyle BackColor="#FFF7E7" ForeColor="#8C4510" />
        <FooterStyle BackColor="#F7DFB5" ForeColor="#8C4510" />
        <PagerStyle ForeColor="#8C4510" HorizontalAlign="Center" />
        <%--<SelectedRowStyle BackColor="#738A9C" Font-Bold="True" ForeColor="White" />--%>
        <HeaderStyle BackColor="#A55129" Font-Bold="True" ForeColor="White" />
    </asp:GridView>`


protected void ResultGridView_RowCommand(object sender, GridViewCommandEventArgs e)
    {
        if (e.CommandName == "Details")
        {
            Server.Transfer("Default3.aspx?ID=" + e.CommandArgument.ToString()); 

        } 

        if (e.CommandName.Equals("AddNew"))
        {

            TextBox txtRegion1 = (TextBox)ResultGridView.FooterRow.FindControl("txtRegion1");
            TextBox txtNatureOFWork1 = (TextBox)ResultGridView.FooterRow.FindControl("txtNatureOFWork1");
            if (txtRegion1.Text != "")
            {
                cmd.Connection = conn;
                cmd.CommandText = "INSERT INTO RegionAndProjectInfo(RegionProjectName, NatureOFWorkID ) Values('" + txtRegion1.Text + "', '" + ddlnatureOfWork.SelectedValue.ToString() + "')";
                conn.Open();
                cmd.ExecuteNonQuery();
            }
            FillVendorGrid();
            conn.Close();
        }
    }
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2 回答 2

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你必须使用

Response.Redirect("Default3.aspx?ID=" + e.CommandArgument.ToString());

而不是服务器传输，因为服务器传输与 Response.Redirect 相比做了不同的事情。

Server.Transfer 方法还有第二个参数——“preserveForm”。如果将此设置为 True，请使用如下语句

`Server.Transfer("Default3.aspx?ID=" + e.CommandArgument.ToString()`, True);

，现有的查询字符串和任何表单变量仍可用于您要转移到的页面。

它更多的是文件传输，而不是重定向

http://msdn.microsoft.com/en-us/library/ms525800%28v=vs.90%29.aspx

于 2012-07-31T05:58:35.767 回答
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<ItemTemplate>
                   <asp:hyperlink id="LinkButton3" navigateurl='<%# "Default3.aspx?ID=" + Eval("RegionProjectID")%>' text='<%# Bind("RegionProjectName")%>' runat="server" />  
                </ItemTemplate>

我已经更新了 Regionprojectname 的 itemtemplate ，现在得到了 query string 。

于 2012-07-31T10:03:03.140 回答