php - php不执行查询

Question

我有两个 mysql 表，这里是他们的 sql =>

我正在用它的子菜单制作动态菜单。所以我有想要执行这样一个查询的情况

DELETE FROM artinfo WHERE descName=(SELECT for_sub_url FROM menu WHERE menu_id=" . $_POST['main_menu_titles'] . ")

其中$_POST['main_menu_titles']存在并且是 menu_id。我也没有编写 php 代码，因为它工作得很好而且值得注意的是，当我试图从 mysql shell 执行它时执行这个查询（当然直接使用 menu_id 的数字而不是 $_POST['m_num']）

任何想法发生了什么，如何从 php 脚本执行它？谢谢 ：）

更新

这是php脚本

if ($connection->query("DELETE FROM artinfo WHERE descName=(SELECT for_sub_url FROM menu WHERE menu_id=" . $_POST['main_menu_titles'] . ")") && $connection->query("DELETE FROM artinfo WHERE descName IS NULL AND cat_id=" . $_POST['main_menu_titles'] . "")){
                            $edit_res_fine = "DELETED";
                        }

Answer 1

If you say the query works just fine without $_POST, I would think the code in question is located in the form you submit to acquire $_POST['main_menu_titles']. To test the correct value is being sent, try echoing the value of $_POST['main_menu_titles'] right before the query.

Answer 2

尝试这个。

$query = "DELETE FROM artinfo WHERE descName = (SELECT for_sub_url FROM menu 
WHERE menu_id = '" . $_POST['m_num'] . "')";