0

我从 SQLite DB 获取行并尝试将它们插入字典。除了我不断收到错误!我收到错误“ARC不允许将Objective-C指针隐式转换为'const id *'”我知道这意味着我在向字典中添加对象时不能使用指针。那么我该如何修复它,以便将这些数组添加到字典中?

    NSArray *keyArray = [[NSMutableArray alloc] init ];
    NSArray *valueArray = [[NSMutableArray alloc ] init ];
    NSDictionary* dic;
    NSInteger dataCount = sqlite3_data_count(statement);
    while (sqlite3_step(statement) == SQLITE_ROW) {
        @try {
            for (int i = 0; i < dataCount; i ++)
            {
                NSString* key = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, i)];  
                NSString *value = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, i)];

                if ([value length] == 0)
                {
                    value = @"";
                }

                keyArray = [keyArray arrayByAddingObject:key];
                valueArray = [valueArray arrayByAddingObject:value];

            }

        }
        @catch (NSException *ex)
        {
            NSLog(@"%@,%@", [ex name], [ex reason]);
        }

        dic= [NSDictionary dictionaryWithObjects:valueArray forKeys:keyArray count:[keyArray count]];
4

2 回答 2

5

dictionaryWithObjects:forKeys:count:接受 C 风格的数组,而不是对象NSArraydictionaryWithObjects:forKeys:可能会解决问题,但是您最好在构建可变字典时完全绕过s NSArray

NSDictionary* dic;
NSMutableDictionary *tmp = [NSMutableDictionary dictionary];

for (int i = 0; i < dataCount; i ++)
{
    NSString* key = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, i)];  
    NSString *value = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, i)];
    [tmp setObject:value forKey:key];
}
dict = tmp;
于 2012-07-30T18:00:30.330 回答
0

[dicBodyPost setValue:arrContactAddress forKey:@"contactAddress"];

于 2017-06-22T13:42:54.373 回答