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我有一个以“日期”为参数的存储过程。

该过程是从一个函数调用的，而该函数又是从 Java 代码调用的。

我将Date来自 Java 代码的作为参数传递。

现在的问题是存储过程没有更新数据库的“日期”列中的正确时间。

得到正确更新，Date但时间使用默认值更新12:00:00AM，而不是原始值。

我使用DBMS_SQL.EXECUTE方法从函数中调用存储过程。

JAVA代码：

 
    import java.sql.CallableStatement;
    import java.sql.ResultSet;

    import org.hibernate.Session;
    import org.hibernate.SessionFactory;
    import org.hibernate.Transaction;
    import org.hibernate.cfg.Configuration;

    public class StackOvFlow {

    /**
    * 
    * @param args
    */

    public static void main(String[] args) {
    String status = "";
    try {
    System.out.println("IN MAIN");

    int userId = 1360822386;
    StringBuffer batchUpdateSQL = new StringBuffer("BEGIN ");
    StringBuffer updateSQLnew = null;
    String date = "30-JUL-2012 10:30:00";

    String currDate = "to_date(" + "'" + date + "'"
    + ",'DD-MON-YYYY HH24:MI:SS')";

    updateSQLnew = new StringBuffer(
    "BEGIN PKG_AMB_LOGIN.P_TRACK_USER("
    + userId
    + ",'" 
    + currDate
    + ""
    + ");Exception When BufferMgr.app_errors_exit Then Rollback; Return; End; ");

    batchUpdateSQL.append(updateSQLnew);

    batchUpdateSQL
    .append(" Exception When BufferMgr.app_errors_exit Then Rollback; Return; End;");

    System.out.println("INPUT ::::");

    System.out.println(batchUpdateSQL);

    String res = getMonthlySave(batchUpdateSQL.toString());
    System.out.println("Response: " + res);

    } catch (Exception e) {
    System.out.println("Exception" + e);
    e.printStackTrace();
    }
    System.out.println(status);

    }

    public static String getMonthlySave(String plSqlBlk) {

    String output = "";
    System.out.println("IN GET MONTHLY SAVE");

    Session session = null;

    CallableStatement cstmt = null;

    ResultSet rs = null;

    SessionFactory sessionFactory = new Configuration().configure(
    "hibernate.cfg.xml")

    .buildSessionFactory();

    session = sessionFactory.openSession();

    Transaction transaction = session.beginTransaction();

    try {

    System.out

    .println("*calling SP **");

    cstmt = session.connection().prepareCall(

    "{? = call PKG_THR.P_UPDT(?,?)}");

    cstmt.setFetchSize(10000);

    cstmt.registerOutParameter(1,

    oracle.jdbc.driver.OracleTypes.CURSOR);
        cstmt.setInt(2,186);

    cstmt.setString(3, plSqlBlk);
    cstmt.execute();

    rs = (ResultSet) cstmt.getObject(1);
    int size = rs.getFetchSize();

    System.out.println("The size of fetch is " + size);

    while (rs.next()) {

    output = output + rs.getString(1);

    }
    System.out.println("OUTPUT ::::::::::::");

    System.out.println(output);

    } catch (Exception e) {

    System.out

    .println("Exception occured in executing query  in fetchdetails....... ");

    e.printStackTrace();

    }

    finally {

    transaction.commit();

    session.close();

    }
    return output;
    }

    }

PL/SQL 功能： 



    CREATE or REPLACE
    PACKAGE BODY PKG_THR AS
    FUNCTION  P_UPDT(login_id number,plsql_block varchar2) RETURN cursor_type IS
    louvtBuff a_XMLBUFFER_TABLE;
    loutRowBuff a_XMLBUFFER_TABLE := a_XMLBUFFER_TABLE();
    EXIT_MESSAGE EXCEPTION;
    lreturn number;
    offset BINARY_INTEGER := 1;
    kount BINARY_INTEGER := 5;
    ln_dbms_cur NUMBER;
    ln_cur_execute NUMBER;
    j number := 1;
    i number;

    buffout cursor_type;
    BEGIN
     BufferMgrXML.CLEARBUFFER;
     BEGIN
     pkg_glbl.g_login_id  := login_id;
     pkg_glbl.g_connect:='1';

     ln_dbms_cur := DBMS_SQL.OPEN_CURSOR;

     DBMS_SQL.PARSE(ln_dbms_cur,plsql_block,DBMS_SQL.NATIVE);

     ln_cur_execute := DBMS_SQL.EXECUTE(ln_dbms_cur);

     EXCEPTION
     WHEN BufferMgr.app_errors_exit then
           lreturn := BufferMgrXML.getXML(louvtBuff,1,1);
           RAISE EXIT_MESSAGE;
     END;

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1 回答 1

2

因为没有太多代码可以观察，所以很难说在这种情况下到底出了什么问题。

非常典型的原因是使用java.sql.Date，它将所有时间字段设置为 0。如果是这种情况，您可以使用java.sql.Timestamp代替（秒的小数部分会丢失）。

于 2012-07-30T13:37:06.880 回答