我已经在这里阅读了一些类似的帖子，但没有成功。我想做的很简单。我有一个非常小的 jquery 移动应用程序，包含在 phonegap 中。在某个页面上，我希望能够访问设备的相机（比如说在 iPhone 上）。我正在使用 phonegap 相机文档中的代码
如果我不使用 jquery mobile，代码本身可以正常工作，但是我想使用 JQM 来设置应用程序的样式。
我知道 JQM 使用 ajax 来调用页面，并且有自己的 pageinit() 和 pageshow() 函数。我怎样才能让 phonegap 和 JQM 一起玩得很好，因为两者都需要触发自己的功能（deviceReady() 和 JQM 是初始化页面）。
如果有帮助，这是我的相机页面代码：
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta name = "format-detection" content = "telephone=no"/>
<meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1, width=device-width;" />
<link rel="stylesheet" type="text/css" href="css/index.css" />
<link rel="stylesheet" type="text/css" href="css/jquery.mobile-1.1.1.css" />
<title>Take Picture</title>
</head>
<body>
<div id="takePicturePage" data-role="page" data-add-back-btn="true">
<div data-role="header" data-position="fixed" id="hrdHome" data-theme="b">
<h1>Take a picture</h1>
</div><!-- /header -->
<div data-role="content" id="content">
<button onclick="capturePhoto();">Capture Photo</button>
<button onclick="capturePhotoEdit();">Capture Editable Photo</button>
<button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From Photo Library</button>
<button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From Photo Album</button>
<img style="display:none;width:60px;height:60px;" id="smallImage" src="" />
<img style="display:none;" id="largeImage" src="" />
</div><!-- /content -->
</div>
<script type="text/javascript" src="cordova-2.0.0.js"></script>
<script type="text/javascript" src="js/jquery-1.7.2.min.js"></script>
<script type="text/javascript" src="js/jquery.mobile-1.1.1.js"></script>
<script type="text/javascript" src="js/takePicture.js"></script>
</body>
</html>
这是我的 takePicture.js：
var pictureSource; // picture source
var destinationType; // sets the format of returned value
// Wait for PhoneGap to connect with the device
//
document.addEventListener("deviceready",onDeviceReady,false);
// PhoneGap is ready to be used!
//
function onDeviceReady() {
pictureSource=navigator.camera.PictureSourceType;
destinationType=navigator.camera.DestinationType;
}
// Called when a photo is successfully retrieved
//
function onPhotoDataSuccess(imageData) {
// Uncomment to view the base64 encoded image data
// console.log(imageData);
// Get image handle
//
var smallImage = document.getElementById('smallImage');
// Unhide image elements
//
smallImage.style.display = 'block';
// Show the captured photo
// The inline CSS rules are used to resize the image
//
smallImage.src = "data:image/jpeg;base64," + imageData;
}
// Called when a photo is successfully retrieved
//
function onPhotoURISuccess(imageURI) {
// Uncomment to view the image file URI
// console.log(imageURI);
// Get image handle
//
var largeImage = document.getElementById('largeImage');
// Unhide image elements
//
largeImage.style.display = 'block';
// Show the captured photo
// The inline CSS rules are used to resize the image
//
largeImage.src = imageURI;
}
// A button will call this function
//
function capturePhoto() {
// Take picture using device camera and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50 });
}
// A button will call this function
//
function capturePhotoEdit() {
// Take picture using device camera, allow edit, and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true });
}
// A button will call this function
//
function getPhoto(source) {
// Retrieve image file location from specified source
navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
destinationType: destinationType.FILE_URI,
sourceType: source });
}
// Called if something bad happens.
//
function onFail(message) {
alert('Failed because: ' + message);
}
请有人帮忙，因为我看不到两者如何一起工作？
提前谢谢了