ios - 如何在 iOS 上快速从 RGB24 转换为 BGRA？

Question

我使用的是vImageConvert_RGB888toARGB8888and vImagePermuteChannels_ARGB8888。先从RGB24改成ARGB，因为OPENGL ES不支持ARGB，所以需要把ARGB改成BGRA用vImagePermuteChannels_ARGB8888. 但是当需要更改的数据很大时，时间成本很高，那么有人有更好的方法吗？谢谢！我的代码是这样的：

- (void)transformRGBToBGRA:(const UInt8 *)pict{
rgb.data = (void *)pict;

vImage_Error error = vImageConvert_RGB888toARGB8888(&rgb,NULL,0,&argb,NO,kvImageNoFlags);
if (error != kvImageNoError) {
    NSLog(@"vImageConvert_RGB888toARGB8888 error");
}

const uint8_t permuteMap[4] = {3,2,1,0};

error = vImagePermuteChannels_ARGB8888(&argb,&bgra,permuteMap,kvImageNoFlags);
if (error != kvImageNoError) {
    NSLog(@"vImagePermuteChannels_ARGB8888 error");
}

free((void *)pict);

}

Answer 1

现在我发现最快的解决方案是组装。像这样：

__asm__ volatile(
                 "0:                \n"
                 "# load 3 64-bit regs with interleave: \n"
                 "vld3.8      {d0,d1,d2}, [%0]!   \n"
                 "# swap d0 and d2 - R and B\n"
                 "vswp d0, d2   \n"
                 "# store 4 64-bit regs: \n"
                 "vst4.8      {d0,d1,d2,d3}, [%2]!      \n"
                 "subs        %1, %1, #1       \n"
                 "bne         0b            \n"
                 :
                 : "r"(img), "r"(numPixels24), "+r"(bgraData)
                 : "r6", "r7","r8"
                 );