知道如何使用 Tornado 在 python 中输出 JSON 对象。任何好的示例、教程、库或输出 JSONP 对象的一行代码。
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2 回答
23
Tornado 提供了tornado.escape.json_encode
,它简单地包装json
在 Python 2.6+ 或simplejson
Python 2.5 上。使用简单:
from tornado.escape import json_encode
obj = {
'foo': 'bar',
'1': 2,
'false': True
}
self.write(json_encode(obj))
输出:
{"1": 2, "foo": "bar", "false": true}
对于 JSONP 响应:
callback = self.get_argument('callback')
jsonp = "{jsfunc}({json});".format(jsfunc=callback,
json=json_encode(obj))
self.set_header('Content-Type', 'application/javascript')
self.write(jsonp)
于 2012-07-27T23:49:53.193 回答
1
您可以以这种方式返回 json obj
import json
class GetYearsHandler(tornado.web.RequestHandler):
def get(self):
try:
response = get_years(self.get_argument("dataset_id"))
result = {'status':'success', 'response': response}
kk = tornado.escape.json_encode(result)
kk = wrap_callback(self, kk)
self.write(kk)
except Exception, e:
print >> sys.stderr, "Error occured:\n%s" % format_exc()
self.write(json.dumps({'status': 'fail', 'error': "Error occured:\n%s" % format_exc()}))
def get_years (dataset_id):
dates=[]
years=[]
conn = condb()
cur = conn.cursor()
data = {'dataset_id':dataset_id}
cur.execute("SELECT layers.start_time FROM layers, datasets WHERE (layers.dataset_id=datasets.id) AND (datasets.business_id=%(dataset_id)s)",data)
for row in cur.fetchall():
dates.append(row[0])
date=""
for date in dates:
year = int(date.year)
if not year in years:
years.append(year)
conn.close()
years.sort()
return years
注册课程
def main(db_fn=None):
tornado.options.parse_command_line()
application = tornado.web.Application([
(r"/get_datasets", GetDatasetsHandler),
(r"/get_years", GetYearsHandler),
)
conn - 是数据库连接
于 2012-07-27T19:53:59.247 回答