我的应用程序的当前锁定概念假定获得 2 个锁并执行代码。但是当我尝试释放第一个锁柄时,总是会出错。有没有办法做到这一点,或者我错误地使用 dbms_lock 一次获得 2 个锁?
此致!
DECLARE
l_handle_1 VARCHAR2(128);
l_handle_2 VARCHAR2(128);
l_result NUMBER;
BEGIN
-- >>> LOCK1
dbms_lock.allocate_unique('lock_1', l_handle_1);
l_result := dbms_lock.request(l_handle_1, dbms_lock.x_mode, 10, true);
BEGIN
-- >>> LOCK2
dbms_lock.allocate_unique('lock_2', l_handle_2);
l_result := dbms_lock.request(l_handle_2, dbms_lock.x_mode, 10, true);
BEGIN
/*
* PLSQL-Code with both locks held
*/
-- LOCK-2 release
l_result := dbms_lock.release(l_handle_2);
IF (l_result > 0) THEN
dbms_output.put_line('Fail 2');
END IF;
-- LOCK-1 release
l_result := dbms_lock.release(l_handle_1);
IF (l_result > 0) THEN
dbms_output.put_line('Fail 1');
END IF;
EXCEPTION
WHEN OTHERS THEN
l_result := dbms_lock.release(l_handle_2);
IF (l_result > 0) THEN
dbms_output.put_line('Fail 3');
END IF;
RAISE;
END;
EXCEPTION
WHEN OTHERS THEN
l_result := dbms_lock.release(l_handle_1);
IF (l_result > 0) THEN
dbms_output.put_line('Fail 4');
END IF;
RAISE;
END;
END;