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我用 PHP 编写了一个简单的搜索脚本。运行时出现空白屏幕并且 PHP 错误日志状态

绑定变量的数量与准备好的语句中的字段数量不匹配

我不明白为什么会这样说，因为我绑定了一个字段 - $searchTitle 和一个绑定参数（字符串）。我的标记很可能完全错误。

任何建议表示赞赏。谢谢。

<?php
if (isset($_POST['btn-search-article'])) {
    $searchTitle = $_POST['search-title'];
    include_once("mysqli_connect.php");
    $table = "articles";  
    $sql = "SELECT title, 
            MATCH(title,category,artbody) 
            AGAINST ('?') 
            AS score
            FROM $table
            ORDER BY score DESC";                
    $stmt = mysqli_stmt_init($dbh);
    if (!(mysqli_stmt_prepare($stmt, $sql))) {
        echo("Write to DB failed ");
    }
    else { //statement prepared ok
        mysqli_stmt_bind_param($stmt, 's', $searchTitle);
        mysqli_stmt_execute($stmt);
        mysqli_stmt_bind_result($stmt, $s1);
        while (mysqli_stmt_fetch($stmt)) {
            echo($s1 . "<br>");
        }
        mysqli_stmt_close($stmt);
    }
} else {
    echo("Error: Search could not be completed");
}
?>

注意：PHP 错误日志指出错误在线

mysqli_stmt_bind_result($stmt, $s1);

修复：似乎 sql 语句的顺序导致了错误。应该

$sql = "SELECT title
        FROM $table
        WHERE MATCH (title, category, artbody)
        AGAINST (?)";
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0 回答 0