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我在 MySQL DB 中有以下 SQL：

select code, distance from locations;

输出如下：

CODE    DISTANCE            LOCATION
106     386.895834130068    New York, NY
80      2116.6747774121     Washington, DC
80      2117.61925131453    Alexandria, VA
106     2563.46708627407    Charlotte, NC
106     2030.5845606766     Atalanta, GA

我希望能够只获得一个代码和最近的距离。所以我希望它返回这个：

CODE    DISTANCE            LOCATION
106     386.895834130068    New York, NY
80      2116.6747774121     Washington, DC

我最初有这样的事情：

SELECT code, min(distance), location
GROUP BY code
HAVING distance > 0 
ORDER BY distance ASC
4

3 回答 3

0

SELECT code, distance, location FROM locations GROUP BY code HAVING distance > 0
ORDER BY distance ASC LIMIT 1

于 2012-07-27T10:35:18.517 回答
0 
  SELECT code, min(distance), location
GROUP BY code,location
  HAVING distance =min(distance)
于 2012-07-27T08:31:42.740 回答
0

尝试这个：

select L.* from (
    SELECT code, min(distance) as min_distance 
    from places
    GROUP BY code)a
join places L
on L.CODE=a.CODE
and L.DISTANCE=a.min_distance
于 2012-07-27T08:46:44.777 回答