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我在调用 mysql 数据库调用soap webservices 的android 应用程序中开发了一个登录表单。它在android 模拟器上成功运行。但在android 真实设备上不起作用。请问我能做什么。请解释这里发生了什么。

我的安卓代码是：

package com.androidlogin.ws;
import java.net.SocketException;
import android.util.Log;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class AndroidLoginExampleActivity extends Activity {
private final String NAMESPACE = "http://ws.userlogin.com";
private final String URL = "http://111.223.128.10:8085/AndroidLogin/services/Login?wsdl";
private final String SOAP_ACTION = "http://ws.userlogin.com/authentication";
private final String METHOD_NAME = "authentication";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    Button login = (Button) findViewById(R.id.btn_login);
    login.setOnClickListener(new View.OnClickListener() {

 public void onClick(View arg0) {
  loginAction();

  }
  });
  }

    private void loginAction(){
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    EditText userName = (EditText) findViewById(R.id.tf_userName);
    String user_Name = userName.getText().toString();
    EditText userPassword = (EditText) findViewById(R.id.tf_password);
    String user_Password = userPassword.getText().toString();

  //Pass value for userName variable of the web service
    PropertyInfo unameProp =new PropertyInfo();
    unameProp.setName("userName");//Define the variable name in the web service method
    unameProp.setValue(user_Name);//set value for userName variable
    unameProp.setType(String.class);//Define the type of the variable
    request.addProperty(unameProp);//Pass properties to the variable

  //Pass value for Password variable of the web service
    PropertyInfo passwordProp =new PropertyInfo();
    passwordProp.setName("password");
    passwordProp.setValue(user_Password);
    passwordProp.setType(String.class);
    request.addProperty(passwordProp);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
     ServiceConnection connection = getServiceConnection();
        connection.connect();
    try{
      connection.setConnectTimeout(60000);
        androidHttpTransport.call(SOAP_ACTION, envelope);
           SoapPrimitive response = (SoapPrimitive)envelope.getResponse();

           TextView result = (TextView) findViewById(R.id.tv_status);
           result.setText(response.toString());

    }


   catch(SocketException ex)
     {
   Log.e("Error : " , "Error on soapPrimitiveData() " + ex.getMessage());
     ex.printStackTrace();
     }

    }
    protected ServiceConnection getServiceConnection() throws IOException {
     return new AndroidServiceConnection(URL);
      }

      }

在我的注销窗口上显示 dis 消息：07-20 04:26:22.728: D/SntpClient(71): request time failed: java.net.SocketException: Address family not supported by protocol

但我的 ip address.port 号码都是正确的。

4

1 回答 1

0

尝试将其添加到您AndroidManifest.xml的：

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

您还需要捕获此异常：

 catch(SocketException ex)
       {
         Log.e("Error : " , "Error on soapPrimitiveData() " + ex.getMessage());
           ex.printStackTrace();
       }

更新

尝试在清单文件中添加以下权限：

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.WAKE_LOCK"/> 
<uses-permission android:name="android.permission.CHANGE_WIFI_STATE" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />

编辑

在 try 块之前添加几行代码：

    ServiceConnection connection = getServiceConnection();
    connection.connect();

在 try 块中，这样写：

     connection.setConnectTimeout(60000); //put a large value for timeout

创建以下方法：

     protected ServiceConnection getServiceConnection() throws IOException {
        return new AndroidServiceConnection(url);
    }

再次运行代码并立即尝试。

于 2012-07-27T06:10:37.940 回答