python - 根据用户对函数的输入访问文件名的一部分——Python

Question

我是一个新手，试图弄清楚如何完成以下任务：

我有以下格式的以用户命名的字典：

<user>_hx

我想使用如下函数访问它们：

def foo(user, other_stuff):
  user_hx[key]

......ETC。

我尝试使用 % 访问如下：

def foo(user, other_stuff):
  %r_hx %user[key]

但由于显而易见的原因，我知道这是行不通的。

建议？

Answer 1

What I think you are asking is how to access a variable based on a string representing its name. Python makes this quite easy:

globals()['%s_hx' % user]

will give you the variable <user>_hx, so you just want

globals()['%s_hx' % user][key]

(I'm not sure whether you should be using globals() or locals(); it will depend on how your variables are defined and where you are trying to access them from)

That said, there is probably an easier/cleaner way to do whatever you are doing. For instance, have you considered putting all these dictionaries in a 'master' dictionary so that you can pass them around, as well as just access them

Answer 2

不要将名称用作变量。您可以将您的字典集合放在另一个顶级字典中，并将这些名称作为键。

users = {
    "user1_hx": {"name": "User 1"},
    "user2_hx": {"name": "User 2"),
    }

等等

然后访问为：

realname = users["%s_hx" % name]["name"]

等等

Answer 3

def foo(user,other_stuff):
     fname = "%s_hx"%user[key] #not sure where key is comming from... but would result in something like "bob_hx"
     with open(fname) as f:
          print f.read()

maybe?/