0

因此，当用户首次打开应用程序时，我会AlertDialog弹出并说出正确的内容。

然后他们可以选择单击 aCheckBox并禁用下次启动应用程序时弹出的对话框。

启用CheckBox无法正常工作。当应用程序完全关闭然后重新启动时，它会再次弹出警报对话框。有人看到我所做的有什么问题吗？

 public static final String PREFS_NAME = "MyPrefsFile1";
 public CheckBox dontShowAgain;

 @Override
 public void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    AlertDialog.Builder adb = new AlertDialog.Builder(this);
    LayoutInflater adbInflater = LayoutInflater.from(this);
    View eulaLayout = adbInflater.inflate(R.layout.custom_dialog, null);
    dontShowAgain = (CheckBox)eulaLayout.findViewById(R.id.checkBox1);
    adb.setView(eulaLayout);
    adb.setTitle("Alert Dialog");
    adb.setMessage("My Customer Alert Dialog Message Body");



    adb.setPositiveButton("Ok", new DialogInterface.OnClickListener()
  {

       //CheckBox Confirm for Alert Dialog
       public void onClick(DialogInterface dialog, int which) {

         String checkBoxResult = "NOT checked";
       if (dontShowAgain.isChecked())  checkBoxResult = "checked";
       SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
       SharedPreferences.Editor editor = settings.edit();
       editor.putString("skipMessage", checkBoxResult); 

            // Commit the edits!
    editor.commit();
    return; 
      }
   });

      adb.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {

             public void onClick(DialogInterface dialog, int which)  {

                             // Action for 'Cancel' Button
                        String checkBoxResult = "NOT checked";
                            if (dontShowAgain.isChecked())  checkBoxResult = "checked";
                            SharedPreferences settings =    getSharedPreferences(PREFS_NAME, 0);
                        SharedPreferences.Editor editor = settings.edit();

                                    editor.putString("skipMessage", checkBoxResult);    
                        // Commit the edits!
                        editor.commit();
                          return;
                    }
    });

                    //Preferences For Alert Dialog
                    SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
                String skipMessage = settings.getString("skipMessage", "NOT checked");
           if (skipMessage !=("checked") )
           adb.setIcon(R.drawable.icon);
           adb.show();

   }

下面是我的AlertDialogXML

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
          android:id="@+id/layout_root"
          android:orientation="horizontal"
          android:layout_width="fill_parent"
          android:layout_height="fill_parent"
          android:padding="10dp"
          >
  <ImageView android:id="@+id/image"
           android:layout_width="wrap_content"
           android:layout_height="fill_parent"
           android:layout_marginRight="10dp"
           />

  <TextView
    android:id="@+id/text"
    android:layout_width="wrap_content"
    android:layout_height="fill_parent"
    android:textColor="#FFF"
    android:textSize="5px" />

  <CheckBox
    android:id="@+id/checkBox1"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="Do Not Show Me This Again" />

</LinearLayout>
4

2 回答 2

3

我看到的问题是您不应该在字符串上使用 == 或 != 。相反，使用 .equals，这样就可以了

if( !skipMessage.equals("checked") )
于 2012-07-25T21:03:55.777 回答
2

如果首选项被“选中”，唯一不会发生的事情skipMessage是将图标设置为 R.drawable.icon。也将其adb.show()放入 if 语句中（用大括号括起来）。

if (!skipMessage.equals("checked") ) {
    adb.show();
}
于 2012-07-25T20:58:32.477 回答