1

我有一个基本模型和代理模型。我想更改“image”字段的upload_to 值，这取决于“file_type”字段。我不确定如何执行此操作，是否需要在我的 .Manager 类或 Proxy 类中指定它。你能否给我同样的细节如何做到这一点。

class FileDescription(models.Model):

    class Meta:
        ordering = ['file_creation_time']

    TYPE_CHOICES = (
        ('homework', 'Homework'),
        ('class', 'Class Papers'),
        ('random', 'Random Papers')                    
    )

    subject = models.ForeignKey('Subjects', null=True, blank=True, primary_key=True)
    subject_name = models.CharField(max_length=100, unique=False)
    file_type = models.CharField(max_length=100, choices=TYPE_CHOICES) 
    ....
    ....
    image = models.ImageField(upload_to= ???????????      blank=True, null=True, max_length=255)

    def __unicode__(self):
        return u'%s' % (self.file_name)

class HomeworkManager(models.Manager):
    def get_query_set(self):
        qs = super(HomeworkManager, self).get_query_set().filter(file_type='homework')
        return qs

class ClassPapersManager(models.Manager):
    def get_query_set(self):
        qs = super(HomeworkManager, self).get_query_set().filter(file_type='class')
        return qs

class RandomPapersManager(models.Manager):
    def get_query_set(self):
        qs = super(HomeworkManager, self).get_query_set().filter(file_type='random')
        return qs

class Homework(FileDescription):

    class Meta:
        proxy = True
4

1 回答 1

2

不要担心替换只是修改方法来处理不同的子类（如果你还没有upload_to使用方法）。upload_to

def my_upload_to(instance, filename):
    if instance._meta.module_name == 'homework':
        return '/path/to/homework/files/%s' % filename
    if instance._meta.module_name == 'classpaper':
        return '/path/to/classpaper/files/%s' % filename
    if instance._meta.module_name == 'randompaper':
        return '/path/to/randompaper/files/%s' % filename
于 2012-07-25T21:09:20.700 回答