sql-server - 选择查询以获取 SQL Server 中的总记录数

Question

嗨，我有一个带有状态列的表。如何使用 SQL 获取记录总数、通过状态的记录总数和失败状态的记录总数？

Answer 1

像这样的东西怎么样：

SELECT Status, COUNT(*)
FROM dbo.YourTable
GROUP BY Status WITH ROLLUP

如果这两种状态（通过，失败）是唯一的状态（否则您将需要WHERE Status IN ('fail', 'pass')另外一个条件），这将起作用 - 并且WITH ROLLUP还将为您提供所有状态的总行数（Status = NULL在输出中带有 a）

Answer 2

我会写一个类似于

select 
Count(*) as TotalRecords, 
Sum(case where status = 'Pass' then 1 else 0 end) as PassRecords,
Sum(case where status = 'Fail' then 1 else 0 end) as FaileRecords
from Table

Answer 3

A couple of other alternatives (SQL Server 2008+):

DECLARE @foo TABLE([status] CHAR(4));

INSERT @foo SELECT 'pass'
UNION ALL SELECT 'pass'
UNION ALL SELECT 'fail';

-- option #1:

SELECT [status], c = COUNT(*)
FROM @foo
GROUP BY GROUPING SETS(([status]), ());

-- option #2:

SELECT [status], c = COUNT(*)
FROM @foo
GROUP BY [status]
UNION ALL 
SELECT NULL, COUNT(*) OVER() FROM @foo;

Answer 4

您可以使用 case 语句和聚合来做到这一点：

select count(*), sum(case when status = 'pass' then 1 else 0 end) as pass,
       sum(case when status = 'fail' then 1 else 0 end) as fail
from t