我的 C++ 知识很糟糕。我有一个 Apple 提供的代码,他们通常提供了一个不完整的解决方案。
在此代码中,它们提供了两个空方法标头:
- (NSString *)encodeBase64:(const uint8_t *)input length:(NSInteger)length
- (NSString *)decodeBase64:(NSString *)input length:(NSInteger *)length
这些方法理论上应该调用两个 C++ 风格的函数,但是由于我的 C++ 知识很臭,无穷平方加一,请填写???
- (NSString *)encodeBase64:(const uint8_t *)input length:(NSInteger)length
{
// I need to call base64_encode and return its results as string... is this correct?
return [NSString stringWithUTF8String:
base64_encode(input, ???)];
// ??? I need to pass a NSInteger to a size_t... how do I do that?
}
- (NSString *)decodeBase64:(NSString *)input length:(NSInteger *)length
{
// ??? = this method receives a NSInteger *length variable. How do I pass that
// to a size_t * variable required by base64_decode?
NSString *st = [[NSString alloc] initWithBytes:
base64_decode([input UTF8String], ???)
length:&length
encoding: NSUTF8StringEncoding];
return st;
}
这 2 个方法调用这些 C++ 函数
char* base64_encode(const void* buf, size_t size)
{
// bla bla bla
}
void* base64_decode(const char* s, size_t* data_len_ptr)
{
// bla bla bla
}
谢谢。