5

我正在尝试打开一个我计划转换为十六进制的二进制文件，但我在通过 FileStream 读取文件时遇到了问题，

private void button1_Click(object sender, EventArgs e)
{
    openFD.Title = "Insert a BIN file";
    openFD.InitialDirectory = "C:"; // Chooses the default location to open the file
    openFD.FileName = " "; // Iniitalizes the File name
    openFD.Filter = "Binary File|*.bin|Text File|*.txt"; // FIlters the types of files allowed to by chosen

    if (openFD.ShowDialog() != DialogResult.Cancel)
    {
        chosenFile = openFD.FileName;
        string directoryPath = Path.GetDirectoryName(chosenFile); // Returns the directory and the file name to reference the file
        string dirName = System.IO.Path.GetDirectoryName(openFD.FileName); // Returns the proper directory with which to refernce the file 
        richTextBox1.Text += dirName;
        richTextBox1.Text += chosenFile;
        FileStream InputBin = new FileStream(
            directoryPath, FileMode.Open, FileAccess.Read, FileShare.None);
    }
}

我收到一条错误消息，提示访问路径被拒绝，有什么想法吗？

现在我已经解决了这个错误，我遇到了另一个问题，我可以读取二进制文件，但我想将它显示为 Hex 文件，我不确定我做错了什么，但我不是在 HEX 中获得输出，它似乎是 Int 值......

if (openFD.ShowDialog() != DialogResult.Cancel)
        {

            chosenFile = openFD.FileName;
            string directoryPath = Path.GetDirectoryName(chosenFile); 
            string dirName = System.IO.Path.GetDirectoryName(openFD.FileName);
            using (FileStream stream = new FileStream(chosenFile, FileMode.Open, FileAccess.Read))
            {
                size = (int)stream.Length;
                data = new byte[size];
                stream.Read(data, 0, size);
            }

            while (printCount < size)
            {
                richTextBox1.Text += data[printCount];
                printCount++;
            }
4

2 回答 2

10

您的代码注释错误

string directoryPath = Path.GetDirectoryName(chosenFile); // Returns the directory and the file name to reference the file

不是文件名，而是目录路径。你要：

FileStream InputBin = new FileStream(chosenFile, FileMode.Open,FileAccess.Read, FileShare.None);

另外，如果我要根据您的意图进行猜测，您应该将您的完整功能更新为：

private void button1_Click(object sender, EventArgs e)
{
    openFD.Title = "Insert a BIN file";
    openFD.InitialDirectory = "C:"; // Chooses the default location to open the file
    openFD.FileName = " "; // Iniitalizes the File name
    openFD.Filter = "Binary File|*.bin|Text File|*.txt"; // FIlters the types of files allowed to by chosen

    if (openFD.ShowDialog() != DialogResult.Cancel)
    {
        chosenFile = openFD.FileName;

        richTextBox1.Text += chosenFile; //You may want to replace this with = unless you mean to append something that is already there.

        FileStream InputBin = new FileStream(chosenFile, FileMode.Open,FileAccess.Read, FileShare.None);
    }
}
于 2012-07-24T18:51:47.863 回答
0

要回答您的第二个问题：

我收到一条错误消息，提示访问路径被拒绝，有什么想法吗？

现在我已经解决了这个错误，我遇到了另一个问题，我可以读取二进制文件，但我想将它显示为 Hex 文件，我不确定我做错了什么，但我不是在 HEX 中获得输出，它似乎是 Int 值......

修改为使用string.Format：

    if (openFD.ShowDialog() != DialogResult.Cancel)
    {

        chosenFile = openFD.FileName;
        string directoryPath = Path.GetDirectoryName(chosenFile); 
        string dirName = System.IO.Path.GetDirectoryName(openFD.FileName);
        using (FileStream stream = new FileStream(chosenFile, FileMode.Open, FileAccess.Read))
        {
            size = (int)stream.Length;
            data = new byte[size];
            stream.Read(data, 0, size);
        }

        while (printCount < size)
        {
            richTextBox1.Text += string.Format( "{0:X} ", data[printCount];
            printCount++;
        }
    }

我已经包含了一个ideone 示例。

于 2012-07-27T16:42:27.150 回答