0

我想在 Ruby 1.8.7 中合并字符串,请帮忙。

s1 = "abc(1,,,,)"
s2 = "abc(,,3,,)"
s3 = "abc(,2,,,)"
s4 = "abc(,,,,5)"

输出应该是:

s = "abc(1,2,3,,5)"

Ruby 1.8.7 中是否有任何内置函数可以实现这一点?

4

1 回答 1

1

大概是这样的?可能不够通用...

def merge *strings
    result_array = strings.inject([]) do |merged_array,string|
        string_content = string[/\((.+?)\)/, 1].split(',', -1)
        string_content.each_with_index do |elem,idx|
            if !merged_array[idx] || merged_array[idx].empty?
                merged_array[idx] = elem 
            end
        end

        merged_array
    end

    $` + '(' + result_array.join(',') + ')' + $'
end

p merge(s1, s2, s3, s4) #=> "abc(1,2,3,,5)"
于 2012-07-24T05:24:22.480 回答