我有这个漂亮的 jquery 脚本,它包含li
s 列表并将它们分组到ul
4li
个以下。
但是有些li
s 有一个特殊的类:<li class="prefslidefeatured">
我希望这个特殊的 li 保持在列表的顶部,因此在第一个 ul 中作为第一个 li。可以有几个被标记为特色的列表,所以我希望它们都留在列表的开头,因此首先是 ul。
我是否可以轻松修改此脚本以适应此新功能?任何想法如何实现这一目标?
我还制作了 jsfiddle 进行快速肮脏测试:) http://jsfiddle.net/sandrodz/5at2G/
//This is for footer slider, it rewrites 1 ul into several uls that contain 4 li max.
$(document).ready(function(){
// get the container, useful for later too...
var container = $(".prefooterslides");
// get all available UL and LI elements...
var li_elements = container.find("LI").clone();
// remove the current content so that we can rebuild it for the slider...
container.find("UL").remove();
// build the slider container...
var slide_container = $("<div />");
slide_container.addClass("slides_container");
// tricky part: looping through the LI's and building each of the slides...
// first create some helpful variables...
var li_elements_per_slide = 4;
var li_counter = 0;
// create the first slide, with a UL to hold the LI's...
var current_li_div = $("<div />");
current_li_div.append($("<ul />"));
// loop through the LI's...
li_elements.each(function(index, element){
li_counter++;
var current_li = $(element).clone();
current_li_div.find("UL").append(current_li);
if (li_counter % li_elements_per_slide == 0)
{
// we've hit 4 in this list, so add the slide and make
// a new one, using same code as before...
container.append(current_li_div);
current_li_div = $("<div />");
current_li_div.append($("<ul />"));
}
});
// we might have an uneven number of LI's, so we need to check for this...
if (li_counter % li_elements_per_slide != 0)
container.append(current_li_div);
// all that's left to do is to initialise the slider script...
$("#prefooterindex").slides({
container: 'prefooterslides',
generatePagination: false
});
});