我在 xsl:for-each-group 中遇到了问题,在这里得到了很好的解决。现在我还有其他问题。我有这样的输入。
<?xml version="1.0" encoding="UTF-8"?>
<body>
<p name ="section">this is section</p>
<p name="h-title" other="main">Introduction</p>
<p name="h1-title " other="other-h1">XSLT and XQuery</p>
<p name="h2-title" other=" other-h2">XSLT</p>
<p name="">
<p1 name="bold"> XSLT is used to write stylesheets.</p1>
</p>
<p name="h2-title " name="other-h2">XQuery</p>
<p name="">
<p1 name="bold"> XQuery is used to query XML databases.</p1>
</p>
<p name="h3-title" name="other-h3">XQuery and stylesheets</p>
<p name="">
<p1 name="bold"> XQuery is used to query XML databases.</p1>
</p>
<p name ="section">this is section</p>
<p name="h1-title " other="other-h1">XSLT and XQuery</p>
<p name="h2-title " other=" other-h2">XSLT</p>
<p name ="section">this is section</section>
<p name="h1-title " other="other-h1">XSLT and XQuery</p>
<p name="h2-title " other=" other-h2">XSLT</p>
</body>
现在我想要的输出是这个
<?xml version="1.0" encoding="UTF-8"?>
<body>
<p name="h-title " other="main">Introduction</p>
<section>
<p name ="section">this is section</p>
<h1>
<p name="h1-title " other="other-h1"> XSLT and XQuery </p>
<h2>
<p name="h2-title " other="other-h2">XSLT</p>
<p name="">
<p1 name="bold">XSLT is used to write stylesheets.
</p1>
</p>
</h2>
<h2>
<p name="h2-title " other="other-h2"> XQuery is used to query XMLdatabases
</p>
<p name="">
<p name="bold"> XQuery is used to query XML databases.</p>
</p>
<h3>
<p name="h3-title " name="other-h3">XQuery and stylesheets</p>
<p name="">
<p1 name="bold"> XQuery is used to query XML databases.</p1>
</p>
</h3>
</h2>
</h1>
</section>
<section>
<p name ="section">this is section</p>
<h1>
<p name="h1-title " other="other-h1">XSLT and XQuery</p>
<h2>
<p name="h2"-title other=" other-h2">XSLT</p>
</h2>
</h1>
</section>
<section>
<p name ="section">this is section</p>
<h1>
<p name="h1-title " other="other-h1">XSLT and XQuery</p>
<h2>
<p name="h2"-title other=" other-h2">XSLT</p>
</h2>
</h1>
</section>
</body>
我用过的样式表(不能正常工作)
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:mf="http://example.com/mf"
exclude-result-prefixes="xs mf">
<xsl:param name="prefix" as="xs:string" select="'h'"/>
<xsl:param name="suffix" as="xs:string" select="'-title'"/>
<xsl:output method="html" version="4.0" indent="yes"/>
<xsl:function name="mf:group" as="node()*">
<xsl:param name="items" as="node()*"/>
<xsl:param name="level" as="xs:integer"/>
<xsl:for-each-group select="$items" group-starting-with="p[@name = concat($prefix,$level, $suffix)]">
<xsl:choose>
<xsl:when test="not(self::p[@name = concat($prefix, $level, $suffix)])">
<xsl:apply-templates select="current-group()"/>
</xsl:when>
<xsl:otherwise>
<xsl:element name="h{$level}">
<xsl:apply-templates select="."/>
<xsl:sequence select="mf:group(current-group() except ., $level + 1)"/>
</xsl:element>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:function>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* , node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="body" name ="myTemplate">
<xsl:copy>
<xsl:sequence select="mf:group(*, 1)"/>
</xsl:copy>
</xsl:template>
<xsl:template match="body[@name='section']">
<section>
<xsl:call-template name="myTemplate"/>
</section>
</xsl:template>
</xsl:stylesheet>
但这是不正确的。诸如此类的事情<p name ="section">this is section</p>
广泛出现。不仅如此,像这样的人很少。如果有人请告诉我如何处理,section
我也可以为其他人做到这一点。请告诉我如何正确执行此操作。
添加
<body>
<intro>
<p></p>
<p></p>
</intro>
<section>
<para>
</para>
<h1></h2>
<h2></h2>
</section>
<section>
<para>
</para>
<h1></h2>
<h2></h2>
</section>
<sumary>
</summary>
</body>
我做了什么
<xsl:for-each-group select="*" group-starting-with="p[@name = 'intro']">
<intro>
<xsl:apply-templates select="current()"/>
</intro>
</xsl:for-each-group>