5

这样做的正确方法是什么？我正在使用 ASP.NET MVC 3。

4

5 回答 5

11 
        DateTime a = ...
        DateTime b = ...
        var ms = a.Subtract(b).TotalMilliseconds;
于 2012-07-23T17:27:10.483 回答
7 
(datetime2 - datetime1).TotalMilliseconds
于 2012-07-23T17:27:14.223 回答
4

我想这应该可行。既然您要求万无一失，我假设您不知道两者中的哪一个是较晚的日期:)

Math.Abs((date1 - date2).TotalMilliseconds)
于 2012-07-23T17:27:37.533 回答
0 
    public static Int64 GetDifferencesBetweenTwoDate(DateTime newDate, DateTime oldDate, string type)
    {
        var span = newDate - oldDate;
        switch (type)
        {
            case "tt": return (int)span.Ticks;
            case "ms": return (int)span.TotalMilliseconds;
            case "ss": return (int)span.TotalSeconds;
            case "mm": return (int)span.TotalMinutes;
            case "hh": return (int)span.TotalHours;
            case "dd": return (int)span.TotalDays;
        }
        return 0;
    }
于 2014-09-05T09:38:00.043 回答
0

减法是我的选择...

DateTime earlier = DateTime.Now;
// ...
DateTime later = DateTime.Now;
double result = (later - earlier).TotalMilliseconds;
于 2012-07-23T17:28:02.523 回答