jquery - 如何获取在使用 YQL 的此函数中未验证的 url 的值？

Question

此示例正确验证 url。如何确定哪些未验证？我想在该部分触发单个警报else或获取值以可能在其他地方使用。

function check_URL() {

var url = "http://" + localStorage['t'] + ".tumblr.com";
var url1 = "http://" + localStorage['t1'] + ".tumblr.com";
var url2 = "http://" + localStorage['t2'] + ".tumblr.com";
var url3 = "http://" + localStorage['t3'] + ".tumblr.com";

var urlArray = ['url', 'url1', 'url2','url3'];
$(urlArray).each(function (urlItem) {
$.getJSON("http://query.yahooapis.com/v1/public/yql?"+
            "q=select%20*%20from%20html%20where%20url%3D%22"+
            encodeURIComponent(urlItem)+
            "%22&format=xml'&callback=?",
    function(data){
      if(data.results[0]){
        console.log("yes");
      } 
      else { 
      console.log("no");

      alert("? is not a valid URL or is down.");

     }
    }
  );
});
};

感谢新手的帮助！

Answer 1

要遍历数组，您需要使用jQuery.each()。

此外，您不需要将变量名称包装在字符串中。这样做只会返回"url"而不是返回变量的值。

function check_URL() {

  var url = "http://" + localStorage['t'] + ".tumblr.com";
  var url1 = "http://" + localStorage['t1'] + ".tumblr.com";
  var url2 = "http://" + localStorage['t2'] + ".tumblr.com";
  var url3 = "http://" + localStorage['t3'] + ".tumblr.com";

  var urlArray = [url, url1, url2, url3],
      invalidUrls = [];

  $.each(urlArray, function (i, urlItem) {
    $.getJSON("http://query.yahooapis.com/v1/public/yql?"+
    "q=select%20*%20from%20html%20where%20url%3D%22"+
    encodeURIComponent(urlItem)+
    "%22&format=xml'&callback=?",
    function(data){
      if(data.results[0]){
        console.log("yes");
      } 
      else { 
        invalidUrls.push(urlItem);
      }
    }
    );
  });

  return invalidUrls;
};