我只有一个 Resource uri,比如'/api/v1/myobjectresource/23/'
,我需要为它补充水分。这意味着,我想从其实例化 MyObject(pk=23) resource_uri
。我该怎么做?
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1 回答
4
摘自https://gist.github.com/794424
def get_resource_uri(self, bundle_or_obj):
kwargs = { 'resource_name': self._meta.resource_name, } if isinstance(bundle_or_obj, Bundle): kwargs['pk'] = bundle_or_obj.obj.id # pk is referenced in ModelResource else: kwargs['pk'] = bundle_or_obj.id if self._meta.api_name is not None: kwargs['api_name'] = self._meta.api_name return self._build_reverse_url('api_dispatch_detail', kwargs = kwargs)
于 2013-01-04T13:22:13.703 回答