6

所以回到基础，我试图围绕 vtables 和诸如此类的东西。在下面的示例中，如果我要将 a 传递B*给某个函数，那么该函数如何知道调用C对象的 vtable 中的方法而不是 的 vtable 中的方法A？是否有两个单独的 VTable 传递给该对象？接口指针真的只是 vtables（因为接口 IIRC 不能包含属性声明）？

我想说的是，在我真正尝试这段代码之前，我一直假设您一次不能继承多个接口/类（并且所有接口都必须是线性的，可以这么说），以便 vtable 建立在自身之上。

如果我对 vtables 如何工作的想法是正确的（我现在知道它不是），那么传递 aB*和被调用B::OutB()就会A:OutA()改为调用（显然不是这种情况）。

有人可以阐明一下吗？

// Includes
#include <windows.h>
#include <iostream>

interface A
{
public:
    virtual void OutA() = 0;
};

interface B
{
public:
    virtual void OutB() = 0;
};

class C : public A, public B
{
public:
    void OutA();
    void OutB();
};

void C::OutA()
{
    printf("Out A\n");
}

void C::OutB()
{
    printf("Out B\n");
}

int main()
{
    C obj;
    obj.OutA();
    obj.OutB();

    A* ap = (A*)&obj;
    B* bp = (B*)&obj;

    ap->OutA();
    bp->OutB();

    system("pause");

    // Return
    return 0;
}

输出（如预期）：

Out A
Out B
Out A
Out B
4

2 回答 2

13

我不知道 aninterface是什么，因为：

  • interface不是C ++ 关键字；
  • C++ 语义中没有“接口”的概念；
  • 不同的 C++ 习语或模式可以将接口一词用于不同的特定目的；
  • 其他语言使用“接口”来描述完全不同的实体（在 Java 中，它就像一种特殊的受限基类，在 O'Caml 中，它用于在 C++ 中您可能使用模板概念的地方）。

但是，如果您正在编写 C++ 并且AandB是类，那么C将包含两个子对象：Aand B，并且这些子对象中的每一个都有自己的 vtable 指针。

在将 C++ 编译为 C 时，我们可以：

#include <stdio.h>
#include <stddef.h>
#include <stdlib.h>

const int debug = 0;

void __pure_virtual_called() {
    fputs ("pure virtual function called\n", stderr);
    abort();
}

/* Translation of:

class A
{
public:
    virtual void OutA() = 0;
};
*/

struct A;

typedef struct  {
    void (*ptr__OutA) (struct A *__this);
} vtable__A;

typedef struct A {
    vtable__A *__vptr;
} A;

/* translation A::OutA() 
 * pure virtual function */
void A__OutA (A *__this) {
     __pure_virtual_called();
}

vtable__A vtable__A__A = { .ptr__OutA = A__OutA };

void A__constructor (A *__this) {
    if (debug)
        printf ("A__constructor %p\n", (void*)__this);

    /* dynamic type is initialised to A */
    __this->__vptr = &vtable__A__A;
}

/* Translation of:

class B
{
public:
    virtual void OutB() = 0;
};

*/

struct B;

typedef struct {
    void (*ptr__OutB)(struct B *__this);
} vtable__B;

typedef struct B {
    vtable__B *__vptr;
} B;

/* translation B::OutB() 
 * pure virtual function */
void B__OutB (B *__this) {
     __pure_virtual_called();
}

vtable__B vtable__B__B = { .ptr__OutB = B__OutB };

void B__constructor (B *__this) {
    if (debug)
        printf ("B__constructor %p\n", (void*)__this);

    /* dynamic type is initialised to B */
    __this->__vptr = &vtable__B__B;
}
/* Translation of:

class C : public A, public B
{
public:
    void OutA(); // overrides A::OutA()
    void OutB(); // overrides B::OutB()
    // note :
    // no new virtual function
};

*/

/* no new virtual function 
 * so no specific vtable type! */

typedef struct {
/* no additional vptr, we already have 2! */
    A base__A;
    B base__B;
} C;

/******* upcasts 
 * translation of 
 * static_cast<C*> (p) 
 */

/* translation of 
 * A *p;
 * static_cast<C*> (p);
 */
C *static_cast__A__C (A *__ptr) {
    /* 
     * base__A is first member of C
     * so offsetof(C, base__A) == 0
     * can skip the pointer adjustment
     */ 
    return (C*)__ptr;
}

/* translation of 
 * B *p;
 * static_cast<C*> (p);
 */
C *static_cast__B__C (B *__ptr) {
    /* locate enclosing C object: 
     * __base__B is not first member
     * need to adjust pointer
     */
    return (C*)((char*)__ptr - offsetof(C, base__B));
}

/* translation of virtual functions of C 
 * overriding function declarations from A
 */

/* translation of C::OutA() */

/* C::OutA() called from C */
void C__OutA (C *__this) {
    printf("Out A this=%p\n", (void*)__this);
}

/* C::OutA() called from A */
void C__A__OutA (A *__this) {
    if (debug)
            printf ("C__A__OutA %p\n", (void*)__this);
    C__OutA (static_cast__A__C (__this));
}

vtable__A vtable__A__C = { .ptr__OutA = C__A__OutA };

/* translation of virtual functions of C 
 * overriding function declarations from B
 */

/* translation of C::OutB() */

/* C::OutB() called from C */
void C__OutB (C *__this) {
    printf("Out B this=%p\n", (void*)__this);
}

/* C::OutB() called from B */
void C__B__OutB (B *__this) {
    if (debug)
            printf ("C__B__OutB %p\n", (void*)__this);
    C__OutB (static_cast__B__C (__this));
}

vtable__B vtable__B__C = { .ptr__OutB = C__B__OutB };

void C__constructor (C *__this) {
    if (debug)
        printf ("C__constructor %p\n", (void*)__this);
    /* construct subobjects */
    A__constructor (&__this->base__A);
    B__constructor (&__this->base__B);

    /* adjust dynamic type of this to C */
    __this->base__A.__vptr = &vtable__A__C;
    __this->base__B.__vptr = &vtable__B__C;
}

/* calls to C virtual functions with a C* 
 */

/* translation of 
 * C *p;
 * p->OutA();
 *
 * is
 * ((A*)p)->OutA();
 *
 * because C::OutA() is overrides A::OutA()
 */
void dyn__C__OutA (C *__this) {
    A *base_ptr__A = &__this->base__A;
    base_ptr__A->__vptr->ptr__OutA (base_ptr__A);
}

/* translation of 

int main()
{
    C obj;
    obj.OutA();
    obj.OutB();

    A *ap = &obj;
    B *bp = &obj;
    C *cp = &obj;

    ap->OutA();
    bp->OutB();
    cp->OutA();

    // Return
    return 0;
}

 *
 */

int main () {
    /* translation of:
    C obj; 
    */
    C obj;
    C__constructor (&obj);

    /* translation of:
    obj.OutA();
    obj.OutB();
     * obj is a locally declared object
     * so dynamic type of obj is known as C
     * can make direct call to C::OutA(), C::OutB()
     */
    C__OutA (&obj);
    C__OutB (&obj);

    /* dumb (zero optimisation) translation of:
    A *ap = &obj;
    B *bp = &obj;
    C *cp = &obj;
    */
    A *ap = &obj.base__A;
    B *bp = &obj.base__B;
    C *cp = &obj;

    /* translation of:
    ap->OutA();
    bp->OutB();
    cp->OutA();

    * dumb compiler = no optimisation
    * so dynamic type of *ap, *bp, *cp is unknown
    * so make "virtual" calls using vtable
    */
    ap->__vptr->ptr__OutA(ap);
    bp->__vptr->ptr__OutB(bp);
    dyn__C__OutA (cp);

    /* note: obj lifetime ends now
     * C has a trivial destructor 
     * so no destructor call needed
     */

    return 0;
}

见http://ideone.com/TioyX

输出：

Out A this=0xbfeee2ec
Out B this=0xbfeee2ec
Out A this=0xbfeee2ec
Out B this=0xbfeee2ec
Out A this=0xbfeee2ec
于 2012-07-24T16:10:14.570 回答
3

通过多重继承，对象被构建成部分，每个部分对应于一个基类。这包括 vtable 指针。这是必要的，因为与指针或引用交互的代码不知道它是在使用基类还是派生类，因此它们的布局必须相同。

一个令人惊讶的结果是，当您将指针转换为一个基类时，它的地址可能会改变！编译器在幕后生成一些代码来调整指针到对象的正确部分。

C obj;
A* ap = (A*)&obj;
B* bp = (B*)&obj;
bool same = ((void*)ap) == ((void*)bp);  // false!
于 2012-07-24T15:56:57.210 回答