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我必须使用所有这些并显示所有这些

SELECT CONVERT(INT,cast(reverse(substring(char_data, 263, 2)) as BINARY(2))) FROM CHAR_DATA0 AS strength
SELECT CONVERT(INT,cast(reverse(substring(char_data, 265, 2)) as BINARY(2))) FROM CHAR_DATA0 AS wisdom
SELECT CONVERT(INT,cast(reverse(substring(char_data, 267, 2)) as BINARY(2))) FROM CHAR_DATA0 AS dexterity
SELECT CONVERT(INT,cast(reverse(substring(char_data, 269, 2)) as BINARY(2))) FROM CHAR_DATA0 AS charisma
SELECT CONVERT(INT,cast(reverse(substring(char_data, 271, 2)) as BINARY(2))) FROM CHAR_DATA0 AS intelligence
SELECT CONVERT(INT,cast(reverse(substring(char_data, 273, 2)) as BINARY(2))) FROM CHAR_DATA0 AS constitution

到目前为止，这是我的 PHP 代码，我尝试使用相同的变量 $result 添加另一个 SQL 查询，因此它也可以用于 $results 的提取，但我没有得到任何结果。

// USING TOP for TEST
$SQL = "SELECT TOP 10 CONVERT(INT,cast(reverse(substring(char_data, 263, 2)) as BINARY(2))) FROM CHAR_DATA0 AS strength";

// Execute query:
$result = mssql_query($SQL) 
    or die('A error occured: ' . mysql_error());
    echo "<table border='1'>
     <tr>
       <th>STR</th>
       <th>WIS</th>
       <th>DEX</th>
       <th>CHA</th>
       <th>INT</th>
       <th>CON</th>
     </tr>";

// Fetch rows:
while ($row = mssql_fetch_assoc($result)) {
     echo "<tr>";
     echo "<td>" . $row['strength'] . "</td>";
     echo "<td>" . $row['wisdom'] . "</td>";
     echo "<td>" . $row['dexterity'] . "</td>";
     echo "<td>" . $row['charisma'] . "</td>";
     echo "<td>" . $row['intelligence'] . "</td>";
     echo "<td>" . $row['constitution'] . "</td>";
     echo "</tr>";  
    }

任何建议，解决方案？我是新来的。谢谢你。

- - - - - - - - - - - - - - - - - - - - - - - - 编辑：无论如何，我该如何排序？

SELECT CONVERT(INT,cast(reverse(substring(char_data, 263, 2)) as BINARY(2))) FROM CHAR_DATA0 AS strength SORT BY char_key WHERE CONVERT(INT, substring(char_data, 261, 1))=0x00 AS permission
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1 回答 1

1

您正在执行 6 个不同的 sql 查询 atm。所以你必须在你的代码中做 6mysql_query和。mysql_fetch_assoc只需执行一个查询：

SELECT
    CONVERT(INT,cast(reverse(substring(char_data, 263, 2)) as BINARY(2))) AS strength,
    CONVERT(INT,cast(reverse(substring(char_data, 265, 2)) as BINARY(2))) AS wisdom,
    CONVERT(INT,cast(reverse(substring(char_data, 267, 2)) as BINARY(2))) AS dexterity,
    CONVERT(INT,cast(reverse(substring(char_data, 269, 2)) as BINARY(2))) AS charisma,
    CONVERT(INT,cast(reverse(substring(char_data, 271, 2)) as BINARY(2))) AS intelligence,
    CONVERT(INT,cast(reverse(substring(char_data, 273, 2)) as BINARY(2))) AS constitution
FROM CHAR_DATA0
于 2012-07-22T07:36:24.250 回答