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我要通过 HttpPost 将歌曲文件发送到服务器。目前我正在使用此代码将数据发送到服务器

HttpPost postRequest = new HttpPost();
        try {

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("email",  Splash.pref.getString("userEmail", "")));
            nameValuePairs.add(new BasicNameValuePair("password", Splash.pref.getString("userPassword", "")));

            nameValuePairs.add(new BasicNameValuePair("name", etName.getText().toString()));
            nameValuePairs.add(new BasicNameValuePair("title", ttfSongTitle.getText().toString()));

            postRequest.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            // construct a URI objectedsta
            postRequest.setURI(new URI(serviceURL));
        } catch (URISyntaxException e) {
            Log.e("URISyntaxException", e.toString());
        }

但是要将歌曲文件发送到服务器，我在网上找到了这段代码，但是在整合这两者时遇到了问题。

String url = "http://yourserver";
File file = new File(Environment.getExternalStorageDirectory(),
        "yourfile");
try {
    HttpClient httpclient = new DefaultHttpClient();

    HttpPost httppost = new HttpPost(url);

    InputStreamEntity reqEntity = new InputStreamEntity(
            new FileInputStream(file), -1);
    reqEntity.setContentType("binary/octet-stream");
    reqEntity.setChunked(true); // Send in multiple parts if needed
    httppost.setEntity(reqEntity);
    HttpResponse response = httpclient.execute(httppost);
    //Do something with response...

} catch (Exception e) {
    // show error
}

请帮助我，以便我可以集成这两者或其他一些解决方案，以便我可以将音乐文件与其他身份验证数据一起发送到服务器。

我正在通过安全的休息服务将数据发送到服务器。

谢谢。

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0 回答 0