我正在尝试开发一个应用程序,允许用户通过实现 Google Places API 来定位附近的机构。但是,没有任何关于如何完成此操作的综合教程/示例。我已经能够拼凑一些代码,但我仍然不知道如何解析结果并随后将它们显示在我的叠加层上。任何帮助是极大的赞赏。
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1 回答
1
您是否知道更具体的问题出在哪里(解析结果或放置引脚)?您看到什么类型的错误?
对于解析 Places API 结果,有一个教程: https ://developers.google.com/academy/apis/maps/places/autocomplete-android
本教程中的以下代码应该可以帮助您开始解析结果。为自动完成和搜索 API 返回的 JSON 相似,但不一样。请务必遵循https://developers.google.com/places/documentation/#PlaceSearchResults中的格式。
private static final String LOG_TAG = "ExampleApp";
private static final String PLACES_API_BASE = "https://maps.googleapis.com/maps/api/place";
private static final String TYPE_AUTOCOMPLETE = "/autocomplete";
private static final String OUT_JSON = "/json";
private static final String API_KEY = "YOUR_API_KEY";
private ArrayList<String> autocomplete(String input) {
ArrayList<String> resultList = null;
HttpURLConnection conn = null;
StringBuilder jsonResults = new StringBuilder();
try {
StringBuilder sb = new StringBuilder(PLACES_API_BASE + TYPE_AUTOCOMPLETE + OUT_JSON);
sb.append("?sensor=false&key=" + API_KEY);
sb.append("&components=country:uk");
sb.append("&input=" + URLEncoder.encode(input, "utf8"));
URL url = new URL(sb.toString());
conn = (HttpURLConnection) url.openConnection();
InputStreamReader in = new InputStreamReader(conn.getInputStream());
// Load the results into a StringBuilder
int read;
char[] buff = new char[1024];
while ((read = in.read(buff)) != -1) {
jsonResults.append(buff, 0, read);
}
} catch (MalformedURLException e) {
Log.e(LOG_TAG, "Error processing Places API URL", e);
return resultList;
} catch (IOException e) {
Log.e(LOG_TAG, "Error connecting to Places API", e);
return resultList;
} finally {
if (conn != null) {
conn.disconnect();
}
}
try {
// Create a JSON object hierarchy from the results
JSONObject jsonObj = new JSONObject(jsonResults.toString());
JSONArray predsJsonArray = jsonObj.getJSONArray("predictions");
// Extract the Place descriptions from the results
resultList = new ArrayList<String>(predsJsonArray.length());
for (int i = 0; i < predsJsonArray.length(); i++) {
resultList.add(predsJsonArray.getJSONObject(i).getString("description"));
}
} catch (JSONException e) {
Log.e(LOG_TAG, "Cannot process JSON results", e);
}
return resultList;
}
于 2012-07-24T00:27:00.337 回答