好吧,我被难住了。我正在使用帮助我上传图片的 Zend 脚本。它工作得很好,但我试图将图片名称捕获到表单的隐藏字段中。我想指出名称发生了变化,所以我需要得到最终被放入隐藏字段的任何一个。这是 Zend 脚本:
<?php
if (isset($_POST['upload'])) {
require_once('scripts/library.php');
try {
$destination = 'xxxxxxxx';
$uploader = new Zend_File_Transfer_Adapter_Http();
$uploader->setDestination($destination);
$filename = $uploader->getFileName(NULL, FALSE);
$uploader->addValidator('Size', FALSE, '90kB');
$uploader->addValidator('ImageSize', FALSE, array('minheight' => 100, 'minwidth' => 100));
if (!$uploader->isValid()) {
$messages = $uploader->getMessages();
} else {
$no_spaces = str_replace(' ', '_', $filename, $renamed);
$uploader->addValidator('Extension', FALSE, 'gif, png, jpg');
$recognized = FALSE;
if ($uploader->isValid()) {
$recognized = TRUE;
} else {
$mime = $uploader->getMimeType();
$acceptable = array('jpg' => 'image/jpeg',
'png' => 'image/png',
'gif' => 'image/gif');
$key = array_search($mime, $acceptable);
if (!$key) {
$messages[] = 'Unrecognized image type';
} else {
$no_spaces = "$no_spaces.$key";
$recognized = TRUE;
$renamed = TRUE;
}
}
$uploader->clearValidators();
if ($recognized) {
$existing = scandir($destination);
if (in_array($no_spaces, $existing)) {
$dot = strrpos($no_spaces, '.');
$base = substr($no_spaces, 0, $dot);
$extension = substr($no_spaces, $dot);
$i = 1;
do {
$no_spaces = $base . '_' . $i++ . $extension;
} while (in_array($no_spaces, $existing));
$renamed = TRUE;
}
$uploader->addFilter('Rename', array('target' => $no_spaces));
$success = $uploader->receive();
if (!$success) {
$messages = $uploader->getMessages();
} else {
$uploaded = "$filename uploaded successfully";
$pic = $filename;
if ($renamed) {
$uploaded .= " and renamed $no_spaces";
}
$messages[] = "$uploaded";
}
}
}
} catch (Exception $e) {
echo $e->getMessage();
}
}
在这里,我试图使$pic
变量暂时不抛出错误(在表单页面上)
if (isset($_POST['upload'])) { } else { $pic = "unknown";}
该$pic
变量是我试图将 zend 脚本中的文件名复制到其中的变量。任何反馈都非常感谢:)