sed - sed 替换 .bashrc 中的 PATH

Question

我的条目中有以下条目.bashrc：

PATH=$PATH:/home/user/abc/bin;export PATH; # ADDED BY INSTALLER - DO NOT EDIT OR DELETE THIS COMMENT

我想替换/home/user/abc/bin我选择的任何路径。我该怎么做sed？

我有以下内容：

sed 's,PATH=[^;]*,PATH=$PATH/home/user/app/2.1,' -i ~/.bashrc

但是，这将替换以 开头的任何内容，PATH我如何指定仅选择以开头PATH但还包括字符串的内容ADDED BY INSTALLER - DO NOT EDIT OR DELETE THIS COMMENT

Answer 1

你这样做：

NEWPATH="your_new_path" sed -i "/ADDED BY INSTALLER - DO NOT EDIT OR DELETE THIS COMMENT/ s:/home/user/abc/bin:$NEWPATH:" .bashrc

Answer 2

锚点位于行首^( ) 和行尾 ( $)，如下所示：

sed -i.bak -e 's,^PATH=[^;]*\(.*ADDED BY INSTALLER - DO NOT EDIT OR DELETE THIS COMMENT\)$,PATH=$PATH/home/user/app/2.1\1,' ~/.bashrc

为了安全起见，我已将.bak后缀添加到就地编辑中。