3

当有人通过我的应用程序工作时，我正在尝试在后台加载图像。我写的逻辑是这样的：

public class ImageLoader extends AsyncTask <Context, Void, Bitmap>{

    private String URL;
    private int type;

    ImageLoader(String Url, int Type)
    {
        URL = Url;
        type = Type;
    }

    @Override
    protected Bitmap doInBackground(Context... arg0) {

        AssetManager assetMgr = arg0[0].getAssets();
        Bitmap bitmap = null;
        try {
            bitmap = BitmapFactory.decodeStream(assetMgr.open(URL));
        } catch (IOException e) {
            e.printStackTrace();
        }
        return bitmap;
    }

    @Override
    protected void onPostExecute( Bitmap result )  {
          super.onPostExecute(result);

          if (type == 1)
              Inst1 = result;
          else if (type == 2)
              Inst2 = result;
          else if (type == 3)
              Inst3 = result;
    }
}

但是，当我尝试像这样开始一个新线程时：

task = new ImageLoader("Instructions_2.png", 3);
task.execute(gameContext);

但是在程序中我得到错误 Looper.prepare 必须被调用，然后是逻辑 looper.quit()

但是，当我添加 Looper.prepare() 时，我似乎破坏了程序，并且没有 looper.quit() 可以调用。

我是否正确创建任务？

编辑：

这是我尝试运行时的错误日志：

task = new ImageLoader(gameContext, "Instructions_3.png", 3);

我有一个 switch case 语句，我将图像加载器声明放在外面。基本上我的代码是：

ImageLoader task;
switch(foo)
{
    case 0:
       ...
       task = new ImageLoader(gameContext, "Instructions_0.png", 3);
       task.execute();
       break;
    case 1:
       ...
       task = new ImageLoader(gameContext, "Instructions_1.png", 3));
       task.execute();
       break;
    ...
}

和错误日志（每次我打task = new ImageLoader(...);线时都会发生错误

07-20 14:23:34.276: E/AndroidRuntime(16741): FATAL EXCEPTION: Thread-10
07-20 14:23:34.276: E/AndroidRuntime(16741): java.lang.ExceptionInInitializerError
07-20 14:23:34.276: E/AndroidRuntime(16741):    at com.petronicarts.stormthecastle.MainGamePanel.update(MainGamePanel.java:2578)
07-20 14:23:34.276: E/AndroidRuntime(16741):    at com.petronicarts.stormthecastle.MainThread.run(MainThread.java:63)
07-20 14:23:34.276: E/AndroidRuntime(16741): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
07-20 14:23:34.276: E/AndroidRuntime(16741):    at android.os.Handler.<init>(Handler.java:121)
07-20 14:23:34.276: E/AndroidRuntime(16741):    at android.os.AsyncTask$InternalHandler.<init>(AsyncTask.java:421)
07-20 14:23:34.276: E/AndroidRuntime(16741):    at android.os.AsyncTask$InternalHandler.<init>(AsyncTask.java:421)
07-20 14:23:34.276: E/AndroidRuntime(16741):    at android.os.AsyncTask.<clinit>(AsyncTask.java:152)
07-20 14:23:34.276: E/AndroidRuntime(16741):    ... 2 more
4

1 回答 1

6

问题是您正试图从非 UI 线程访问和操作 UI 元素。如果你改变你AsyncTask的如下，我相信你会没事的：

public class ImageLoader extends AsyncTask <Void, Void, Bitmap>{

private String URL;
private int type;
private Context context;
private InputStream in;

ImageLoader(Context context, String Url, int Type)
{
    URL = Url;
    type = Type;
    ImageLoader.this.context = context;
}

@Override
protected void onPreExecute()
{
   AssetManager assetMgr = context.getAssets();

   try {

       in = assetMgr.open(URL);
   } catch (IOException e) {

       e.printStackTrace();
   }

}

@Override
protected Bitmap doInBackground(Void... arg0) {

    Bitmap bitmap = null;
    try {
        bitmap = BitmapFactory.decodeStream(in);
        in.close();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return bitmap;
}

@Override
protected void onPostExecute( Bitmap result )  {

      if (type == 1)
          Inst1 = result;
      else if (type == 2)
          Inst2 = result;
      else if (type == 3)
          Inst3 = result;
}
}

还将您的呼叫更改为AyncTask以下内容：

task = new ImageLoader(gameContext, "Instructions_2.png", 3);
task.execute();
于 2012-07-20T19:13:48.270 回答